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faltersainse [42]
4 years ago
14

A rectangle is 4 cm longer than it is wide, and its area is 117 cm2 . find its dimensions.

Mathematics
2 answers:
Orlov [11]4 years ago
7 0

Answer:

Step-by-step explanation:

its 13 cm

Brilliant_brown [7]4 years ago
3 0
The area of a rectangle is equal  L x  W   

4 cm longer than it is wide   L = 4 + <span>W
</span>
L x  W = 117     we replace L here 

(4 + <span>W ) x W = 117 
</span>
4W + W ^2  = 117 

<span>4W + W ^2  -117 = 0
</span>W ^2 +4 W -117 = 0

W² + 4W - 117 = 0

<span>
THEN u want to use the </span>use the quadratic formula
 

OR Factoring gives us

(W + 13)(W - 9) = 0

W = -13 or 9

But it can't be negative, so

W = 9  and L= 9+4 = 13
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Please help on these two​
jeyben [28]

Answer:

For your first problem you want to see what all the sides would equal

You would have to combine them all into one big equation

5x-7+3x+1+4x=30 (now you want to combine like terms)

12x-7+1=30 (combined the x's together)

12x-6=30 (added -7 and 1)

12x=36 (added 6 to each side)

x=3 (divided 12 to each side)

Now you wanna plug 4 in for x for each side to find out the largest to smallest

AB=5(3)-7= 8

BC=3(3)+1= 10

AC=4(3)= 12

So in order from smallest to largest would be angle C, B, A because

Angle C is the smallest angle because the sides AC and BC are the longest so they form the smallest angle

Then it would be angle A being the largest because the smallest sides in length AB and BC make up the biggest angle

The next problem would be that in order for it to have to be a triangle the two smallest sides needs to add up higher than the third side so

11, 11, 24, 11+11=22, which is less than 24 so not this one

18,12,9, 9+12=21 which is greater that 18 so this one would be a triangle

9,10,19, 9+10=19 which 19 isn't greater than 19 so this one is not a triangle

4,7,23, 4+7=11 which is less than 23, so this one is also not a triangle

So your answer would be 18cm,12cm,9cm

8 0
3 years ago
The domain of y=ax^2 is all real numbers. Describe the range when (a) a&gt;0 and (b) a&lt;0.
eduard
The range is all positive values...

R{y | y>0}

Range > "Y" such that y is greater than 0
3 0
3 years ago
Show how you got the answer
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3 0
4 years ago
Find the sum of 8a –2b + 3c and –3a +4b –3c<br>​
IRISSAK [1]
ANSWER:
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add the like terms together

4 0
3 years ago
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