A rectangle is 4 cm longer than it is wide, and its area is 117 cm2 . find its dimensions.
2 answers:
Answer:
Step-by-step explanation:
its 13 cm
The area of a rectangle is equal L x W
4 cm longer than it is wide L = 4 + <span>W
</span>
L x W = 117 we replace L here
(4 + <span>W ) x W = 117
</span>
4W + W ^2 = 117
<span>4W + W ^2 -117 = 0
</span>W ^2 +4 W -117 = 0
W² + 4W - 117 = 0
<span>
THEN u want to use the </span>use the quadratic formula
OR Factoring gives us
(W + 13)(W - 9) = 0
W = -13 or 9
But it can't be negative, so
W = 9 and L= 9+4 = 13
You might be interested in
Answer:
D
Step-by-step explanation:
7/9 because if you simplify 21/27 you have to divide it by something that can go into both equally, which in this case is 3
Answer:
x = 12
Step-by-step explanation:
set up a proportion:
<u> 24 </u> = <u> 32 </u>
33 32+x
24(32 + x) = 32(33)
768 + 24x = 1056
24x = 288
x = 12
Answer:
The end equation you get is p = 6x - 8
Step-by-step explanation:
p = 2l + 2w
p = 2(x + 5) + 2(2x - 9)
p = 2x + 10 + 4x - 18
p = 6x - 8
<span>(-2,7)
(18,1)
Slope = difference in "y" / </span><span>difference in "x"
Slope = 7 - 1 / -2 -18
</span>
<span>Slope = -6 / -20
Answer is 2) -3 / 10
</span>