A rectangle is 4 cm longer than it is wide, and its area is 117 cm2 . find its dimensions.

Mathematics

2 answers:

Orlov [11]3 years ago

7 0

Answer:

Step-by-step explanation:

its 13 cm

Brilliant_brown [7]3 years ago

3 0

The area of a rectangle is equal L x W

4 cm longer than it is wide L = 4 + W

L x W = 117 we replace L here

(4 + W ) x W = 117

4W + W ^2 = 117

4W + W ^2 -117 = 0
W ^2 +4 W -117 = 0

W² + 4W - 117 = 0


THEN u want to use the use the quadratic formula

OR Factoring gives us

(W + 13)(W - 9) = 0

W = -13 or 9

But it can't be negative, so

W = 9 and L= 9+4 = 13

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¿Can i get the answer?

NikAS [45]

Answer:

15.7

Step-by-step explanation:

5 x 3.14(pi) = 15.7

3 0

2 years ago

The perimeters of the square and the triangle shown below are equal. What is the value of x?

Rudiy27

Perimeter is the sum of all the sides. So we can set up an equation:

$\sf 3x+1+3x+1+3x+1+3x+1=2x+8+x+8+4x+2$

Now solve for 'x', combine like terms:

When it comes to terms with variables it's just like normal addition but we keep the variable:

$\sf 3x+3x+3x+3x=12x$
$\sf 2x+x+4x=7x$

So we have:

$\sf 12x+1+1+1+1=7x+8+8+2$

Add:

$\sf 12x+4=7x+18$

Subtract 7x to both sides:

$\sf 5x+4=18$

Subtract 4 to both sides:

$\sf 5x=14$

Divide 5 to both sides:

$\boxed{\sf x=2.8}$