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Novay_Z [31]
3 years ago
6

Help! 10 Points not 5!

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
6 0

9514 1404 393

Answer:

  18

Step-by-step explanation:

Solve the first for a, then substitute into the second.

  a = 27/(5b^2)

Then ...

  (27/(5b^2))^2·b = 135

  27^2/(5^2·135) = b^3 = 27/125

  b = ∛(27/125) = 3/5

  a = 27/(5(3/5)^2) = 15

__

The expression of interest is ...

  a +5b = 15 + 5(3/5) = 15 +3

  a +5b = 18

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Answer:

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Step-by-step explanation:

Please see the Newton's 2nd Law which states  that an object accelerates if there is a net or unbalanced force on it. In this scenario there is just one force exerted on the wagon i.e: the force that the horse exerts on it. The wagon accelerates because the horse pulls on it. And the amount of acceleration equals the net force on the wagon divided by its mass.

As there are two forces the push and pull the horse; the wagon pulls the horse backwards, and the ground pushes the horse forward. The net force is determined by the relative sizes of these two forces.

If the ground pushes harder on the horse than the wagon pulls, there is a net force in the forward direction, and the horse accelerates forward, and if the wagon pulls harder on the horse than the ground pushes, there is a net force in the backward direction, and the horse accelerates backward.

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7 0
3 years ago
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If mc008-1.jpg, what is f(5.9)?
yulyashka [42]
The answer:

the full question is if f(x) = 3 [ x - 2 ] , what is f(5.9)?

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<span>12

</span>first, [x - 2 ] is called the integer part of x-2, 
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so <span>f(5.9) = 3 [ 5.9 - 2 ] =  3 [ 3.9 ]

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3 years ago
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ValentinkaMS [17]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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