Answer:
Step-by-step explanation:
Instead, since the divisor is in the form of 
, use what is called Synthetic Division. Remember, in this formula, 
gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
4| 1 −5 7 −12
↓ 4 −4 12
_______________
1 −1 3 0 →
You start by placing the 
in the top left corner, then list all the coefficients of your dividend [x³ - 5x² + 7x - 12]. You bring down the original term closest to then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an 
, the −1 [
] follows right behind it, and bringing up the rear, comes the 3, giving you the quotient of .
I am joyous to assist you anytime.
Answer:
of the cake
Step-by-step explanation:
add 
and 
to see the total amount of cake eaten.
a. find the common denominator: 8 x 3 = 24 and 6 x 4 = 24
b. multiply accordingly to get the correct numerator: 
+ 
c. add: + = 
subtract found value from total to find left over cake.
a. 24 - 7 = 14
simplify.
a. 
=
You are left with of the cake.
Answer:
Step-by-step explanation:
given D : (7,-3), and D' : (2,5)
the coordinates of D can be represented as (x1,y1), and the coordinates of D' can be represented as (x,y).
you can simply take the difference in the x values and difference in the y values from the preimage to image.
like this:
f'(x,y) → f(x+(x-x1),y+(y-y1)) : 
D'(x,y) → D(x+(2-7),y+(5--3))
D'(x,y) → D(x<u>-5</u>,y<u>+8</u>) : 
Answer:
Y=6x-4
Step-by-step explanation:
Y=mx+b
in this cace we have m- the slope
Y=6x+b
now we can plug in the coordinates to solve for b- the y intercept
(1,2) 1 being the x value, and 2 being the y value
2= 1·6+b
2=6+b
-4=b
now we take our previous equation, and add to it
Y=6x-4
(x + y)^2 = (x^2 - 2xy + y^2)
First distribute the ^2 on the left side of the equation to each term inside the parenthesis:
x^2+ 2xy + y^2
Now pick one of the variables to solve for and isolate it:
(solving for x)
x^2 + 2xy + y^2 = x^2 - 2xy + y^2
x^2+ 2xy = x^2 - 2xy
2xy = -2xy
-x = x
x = 0
When you solve for y in the equation it will turn out to be 0 as well
