Ask question

Ask question

All categories

Bad White [126]

4 years ago

5

Which sequence follows the rule 2n + 6, where n represents the position of a term in a sequence? 6, 8, 12, 18, . . . 6, 12, 18,

24, . . . 8, 14, 20, 26, . . . 8, 10, 12, 14, . . .

1 answer:

melamori03 [73]4 years ago

8 0

ANSWER

8, 10, 12, 14, . . .

EXPLANATION

The given rule for the sequence is :

f(n)=2n+6

The domain for a sequence is the set of natural numbers.

When n=1,

f(1)=2(1)+6=8

When n=2,

f(2)=2(2)+6=10

When n=3,

f(3)=2(3)+6=12

When n=4,

f(4)=2(4)+6=14

Therefore the sequence that follows the given rule is

8, 10, 12, 14, . . .

You might be interested in

Winston bought an encyclopedia priced at $42. Shipping and handling cost anadditional 30% of the price. What was the total cost

Sergio039 [100]

Answer:

42.3

Sorry I haven't been answering your questions I'm just behind on homework.

3 0

3 years ago

2. Jessica's dining room in her new townhouse is 11 feet wide by 12 feet deep. How many square feet is it?

aliina [53]

Answer:

132 sq ft

Step-by-step explanation:

7 0

3 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

IgorC [24]

Answer:

$9.99\text{secs}$

Explanation:

Here, we want to find the time the rocket will hit the ground

What we have to do is to substitute 0 for the height of the rocket y and solve the quadratic equation that results

That simply means we are solving for:

$0=-16x^2+149x+108$

We can use the quadratic formula to solve this

$x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

where a is the coefficient of x^2 which is -16

b is the coefficient of x which is 149

c is the last number which is 108

Substituting the values, we have it that:

$\begin{gathered} x\text{ = }\frac{-149\pm\sqrt[]{149^2-4(-16)(108)}}{2(-16)} \\ \\ x\text{ = }\frac{-149\pm\sqrt[]{29113}}{-32}\text{ } \\ \\ x\text{ = }\frac{-149-170.625\text{ }}{-32} \\ or\text{ } \\ x\text{ = }\frac{-149_{}+170.625}{-32} \end{gathered}$

Now, we proceed to get the individual x-values:

$\begin{gathered} x\text{ = }\frac{-149-170.625}{-32}\text{ = 9.99 } \\ or \\ x\text{ = }\frac{-149+170.625}{-32}\text{ = -0.68} \end{gathered}$

Since time cannot be negative, we use the first value only

6 0

1 year ago

PLEASE HELP!!! WILL MARK BRAINLIEST!! THX! A golfer hits a ball with an initial velocity of 32.7 m/s from the ground. Find the f

OLEGan [10]

Answer:

See below

Step-by-step explanation:

<u>First Problem</u>

The ball hits the ground when $h(t)=0$ , therefore:

$h(t)=-4.9t^2+v_0t+h_0$

$0=-4.9t^2+32.7t$

$0=t(-4.9t+32.7)$

$t=0$ and $t=\frac{32.7}{4.9}\approx6.67$

Since the ball is in the air before it hits the ground, $t=6.67$ (seconds) is the more appropriate choice.

<u>Second Problem</u>

The maximum height of the ball is determined when $t=-\frac{b}{2a}$ , therefore:

$t=-\frac{b}{2a}$

$t=-\frac{32.7}{2(-4.9)}$

$t=-\frac{32.7}{-9.8}$

$t\approx3.34$

This means that the height of the ball is at its maximum after 3.34 seconds:

$h(t)=-4.9t^2+32.7t$

$h(3.34)=-4.9(3.34)^2+32.7(3.34)$

$h(3.34)\approx54.55$

Thus, the answer is 54.55 (meters).

<u>Third Problem</u>

Refer to the second problem

<u>Fourth Problem</u>

<u /> $h(t)=-4.9t^2+32.7t$ <u />

<u /> $h(4.3)=-4.9(4.3)^2+32.7(4.3)$ <u />

<u /> $h(4.3)\approx50.01$ <u />

<u />

Therefore, the height of the ball after 4.3 seconds is 50.01 (meters).

<u>Fifth Problem</u>

The ball will be 24 meters off the ground when $h(t)=24$ , therefore:

$h(t)=-4.9t^2+32.7t$

$24=-4.9t^2+32.7t$

$0=-4.9t^2+32.7t-24$

$t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$t=\frac{-32.7\pm\sqrt{(32.7)^2-4(-4.9)(-24)}}{2(-4.9)}$

$t_1\approx0.84$

$t_2\approx5.83$

Therefore, the ball will be 24 meters off the ground after 0.84 (seconds) and 5.83 (seconds)

5 0

2 years ago

A balloon is released from the top of a building. The graph shows the height of the balloon over time . What does the slope and

lilavasa [31]

I think it is B I am not exactly sure please check to make sure I am right

3 0

3 years ago