Answer:
42.3
Sorry I haven't been answering your questions I'm just behind on homework.
Answer:
132 sq ft
Step-by-step explanation:
Answer:

Explanation:
Here, we want to find the time the rocket will hit the ground
What we have to do is to substitute 0 for the height of the rocket y and solve the quadratic equation that results
That simply means we are solving for:

We can use the quadratic formula to solve this
![x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
where a is the coefficient of x^2 which is -16
b is the coefficient of x which is 149
c is the last number which is 108
Substituting the values, we have it that:
![\begin{gathered} x\text{ = }\frac{-149\pm\sqrt[]{149^2-4(-16)(108)}}{2(-16)} \\ \\ x\text{ = }\frac{-149\pm\sqrt[]{29113}}{-32}\text{ } \\ \\ x\text{ = }\frac{-149-170.625\text{ }}{-32} \\ or\text{ } \\ x\text{ = }\frac{-149_{}+170.625}{-32} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-149%5Cpm%5Csqrt%5B%5D%7B149%5E2-4%28-16%29%28108%29%7D%7D%7B2%28-16%29%7D%20%5C%5C%20%20%5C%5C%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-149%5Cpm%5Csqrt%5B%5D%7B29113%7D%7D%7B-32%7D%5Ctext%7B%20%7D%20%5C%5C%20%20%5C%5C%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-149-170.625%5Ctext%7B%20%20%20%7D%7D%7B-32%7D%20%5C%5C%20or%5Ctext%7B%20%7D%20%5C%5C%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-149_%7B%7D%2B170.625%7D%7B-32%7D%20%5Cend%7Bgathered%7D)
Now, we proceed to get the individual x-values:

Since time cannot be negative, we use the first value only
Answer:
See below
Step-by-step explanation:
<u>First Problem</u>
The ball hits the ground when
, therefore:



and 
Since the ball is in the air before it hits the ground,
(seconds) is the more appropriate choice.
<u>Second Problem</u>
The maximum height of the ball is determined when
, therefore:




This means that the height of the ball is at its maximum after 3.34 seconds:



Thus, the answer is 54.55 (meters).
<u>Third Problem</u>
Refer to the second problem
<u>Fourth Problem</u>
<u />
<u />
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Therefore, the height of the ball after 4.3 seconds is 50.01 (meters).
<u>Fifth Problem</u>
The ball will be 24 meters off the ground when
, therefore:







Therefore, the ball will be 24 meters off the ground after 0.84 (seconds) and 5.83 (seconds)
I think it is B I am not exactly sure please check to make sure I am right