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love history [14]
2 years ago
6

Help pls!! I only have 1/2 hours to finish :(( on the scale drawing of a car, the length from bumper to bumper is 6 inches. the

car’s actual length, from bumper to bumper, is 16 feet. using I to represent inches and to F represent feet, write two equations to express the rate relationship
Mathematics
1 answer:
notka56 [123]2 years ago
3 0

Answer:

I = 3\8 . F and F = 8\3 . I

Step-by-step explanation:

Hope this helps! ;3

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Answer:

32 days is my final answer

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What is the result when the number 86 is decreased by 9%?
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78.26

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Find the quotient of the quantity negative 6 times x to the 2nd power times y to the 8th power plus 12 times x times y to the 3r
olga nikolaevna [1]
[ - 6 * x^2 * y^8 + 12*  x * y^3 - 36 * x * y^2 ] / [6*x*y^2] =

[-6x^2 y^8 ] / [6xy^2] + [12x y^3] / [6xy^2] - [36xy^2] / [6xy^2] =

- xy^6 + 2y - 6

Answer: - xy^6 + 2y - 6

6 0
3 years ago
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What is the midpoint M of that line segment?
pychu [463]

Answer:

Midpoint = (  (x1+x2)/2 , (y1+y2)/2 )

Step-by-step explanation:

Please upload the line segment otherwise, you can use the equation above to solve for it.

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3 years ago
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The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is soli
stiks02 [169]
The first line through points (-3, 0) and (-4, -1) is the orange line.

The second line, through (1, 1) and (2, -1) is the purple line.

Since they are both shaded below, the intersection of the shaded regions, is the region colored in blue.

Both lines are included, since they are solid lines.



The equation of the first line can be found as follows:

the slope is \frac{0-(-1)}{-3-(-4)}=\frac{1}{1}=1, thus, the equation is:
y-0=1(x-(-4))\\\\y=x+4


The equation of the second line can be found as follows:

the slope is \frac{1-(-1)}{1-2}= \frac{2}{-1}=-2, 

thus the equation of the second line is :


y-1=-2(x-1)\\\\y-1=-2x+2\\\\y=-2x+3


We have to decide on the direction of the inequality sign, so we pick a point, for example (0, 4) which is not in the colored regions of the lines, 

so we write the inequalities so that they do not hold for (0, 4)


line 1:

y≥x+4

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y≤-2x+3

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Note that since the lines were solid, we include the equality case:


Answer: 

the shaded region is the solution to the system of inequalities:

i) y≤x+4
ii) y≤-2x+3

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