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swat32
3 years ago
6

Solve for x and y

Mathematics
2 answers:
velikii [3]3 years ago
8 0

<u>Answer:</u>

The correct answer option is a) there are an infinite number of solutions

<u>Step-by-step explanation:</u>

We are given these two following equations:

15x = 5y - 5 --- (1)

y = 3x + 1 --- (2)

Solving these two by the substitution method by putting the value of y in equation (1).

15x = 5y - 5

15x = 5(3x + 1) - 1

15x = 15x + 5 - 5

5 and -5 get cancelled and we are left with 15 on both sides of the equation which will cancel each other.

Therefore, these equations have an infinite number of solutions.

Rainbow [258]3 years ago
5 0
The answer would be option B
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Lorico [155]

Answer:

Given that the question rightly asks the amount it cost to drive from Smithville to Jones City, we have;

The question rightly asks the amount it cost to drive from Smithville to Jones City is approximately $7.209

Step-by-step explanation:

The coordinates of Smithville is (-25, 10)

The coordinates of Jones City is (15, 12)

The cost of driving a car for a mile = $0.18

Therefore, the distance from Smithville to Jones City is given by the formula for the distance, l, between two points with coordinates as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

(x₁, y₁) = (-25, 10) and (x₂, y₂) = (15, 12)

l = \sqrt{\left (12-10  \right )^{2}+\left (15-(-25)  \right )^{2}} = 2 \cdot \sqrt{401}

The distance from Smithville to Jones City = 2·√401 ≈ 40.05 miles

The amount, A, it cost to drive from Smithville to Jones City a distance of approximately 40.05 miles is therefore given as follows;

A = 40.05 miles × $0.18 ≈ $7.209

8 0
3 years ago
An online furniture store sells chairs for $150 each and tables for $550 each. Every day, the store can ship a maximum of 40 pie
Katen [24]

Answer:

minimum of 13 chairs must be sold to reach a target of $6500

and a max of 20 chairs can be solved.

Step-by-step explanation:

Given that:

Price of chair = $150

Price of table = $400

Let the number of chairs be denoted by c and tables by t,

According to given condition:

t + c = 30 ----------- eq1

t(150) + c(400) = 6500 ------ eq2

Given that:

10 tables were sold so:

t = 10

Putting in eq1

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As the minimum target is $6500 so from eq2

10(150) + 400c = 6500

400c = 6500 - 1500

400c = 5000

c = 5000/400

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c = 13

So a minimum of 13 chairs must be sold to reach a target of $6500

i hope it will help you! mark me as brainliest pls

§ALEX§

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3 years ago
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PtichkaEL [24]

Answer:

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8 0
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