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3 years ago

Help me asap!!!!!!! please!!!

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

6 0

Answer:

see attachment

Step-by-step explanation:

The applicable property of exponents is ...

$\sqrt[n]{x^m}=x^{\frac{m}{n}}$

The 4th selection uses this property directly. The 3rd selection uses the property

$(a^b)^c=a^{bc}$

to show that the cubes of the two expressions are equivalent. Since all the numbers involved are real numbers, this is equivalent to showing the expressions equivalent.

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What is the surface area of this triangular prism rounded to the nearest tenth?

Vesna [10]

The answer is C.
SA = bh + (s1 + s2 + s3)H
SA = (6.8)(5.1) + (6.8 + 5.1 + 8.5)(2.5) = 85.68

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2 years ago

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A rectangular sand box has a length of 5 1/3 feet and a width of 3 3/4 feet. What is the perimeter in mixed number?

Vadim26 [7]

Answer: 18 1/6 feet

Step-by-step explanation:

From the question, we are informed that the rectangular sand box has a length of 5 1/3 feet and a width of 3 3/4 feet.

The perimeter would be calculated as:

= 2(length + width)

= 2( 5 1/3 + 3 3/4)

= 2( 5 4/12 + 3 9/12)

= 2( 8 13/12)

= 2 (9 1/12)

= 2 × 9 1/12

= 2 × 109/12

= 218/12

= 18 2/12

= 18 1/6 feet

5 0

2 years ago

Find the diameter of a cone that has a volume of 56.52 cubic inches and a height of 6 inches. Use 3.14 for pi. a. 3 inches. b. 6

sergejj [24]

Volume of cone = (1/3)pi*r²h

56.52 = (1/3)*3.14*r²*6

56.52/(2*3.14) = r²

9 = r²

r² = 9

r = √9

r = 3

Diameter = 2*r = 2*3 = 6 inches. b.

3 0

3 years ago

In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist

Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

$np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96$

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

$\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408$

#Define Y:

Y~(11.04,5.7408)

$P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291$

Hence, the probability of 12 or fewer is 0.8291

b. The probability that 5 or more fish were caught.

#Using normal approximation:

$P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968$

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above $P(X\geq 5)=0.9968$ and a , $P(X\leq 12)$ =0.7291

$P(5\leq X\leq 120\approx P(4.5\leq Y\leq 12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259$

Hence, the probability of between 5 and 12 is 0.7259

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2 years ago

What is the answer to y=2x-9

stiv31 [10]

Sorry to break it to you, but...

That's a line equation my dude. There's no answer.

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2 years ago

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