Answer:
s=salary
x=sales
s ≥ 4,000 + .06x
Step-by-step explanation:
So for this, I will be using the substitution method. Firstly, subtract both sides in the second equation by 2x: 
Next, substitute y in the first equation with 7-2x, then solve for x from there:

Now that we got x, substitute it into either equation to solve for y:

In short, x = 1/2 and y = 6.
There are 62 quarters and 52 dimes in the jar.
Step-by-step explanation:
Given,
Worth of jar coins = $20.70 = 20.70*100 = 2070 cents
1 Quarter = 25 cents
1 Dime = 10 cents
Let,
Number of quarters = x
Number of dimes = y
According to given statement;
25x+10y=2070 Eqn 1
x=y+10 Eqn 2
Putting value of x from Eqn 2 in Eqn 1

Dividing both sides by 35

Putting y=52 in Eqn 2

There are 62 quarters and 52 dimes in the jar.
Keywords: linear equation, substitution method
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Answer:
c
Step-by-step explanation:
im not completely sure