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Ivanshal [37]
3 years ago
15

The Model Company is to begin operations in April. It has budgeted April sales of $30,000, May sales of $34,000, June sales of $

40,000, July sales of $42,000, and August sales of $38,000. Note that 10% of each month's sales is expected to represent cash sales; 75% of the balance is expected to be collected in the month following the sale, 17% the second month, 6% the third month, and the balance is expected to be uncollectible. What is the amount of cash to be collected in the month of July?
Business
2 answers:
pashok25 [27]3 years ago
8 0

Answer:

$38,022

Explanation:

Given that the cash collection model is such that 10% of each month's sales is expected to represent cash sales; 75% of the balance is expected to be collected in the month following the sale, 17% the second month, 6% the third month, and the balance is expected to be uncollectible, it means that collection for July would include;

  • 10% sales in July
  • 75% of 90% of sales in June
  • 17% of 90% of sales in May
  • 6% of 90% of sales in April

Hence, if It has budgeted April sales of $30,000, May sales of $34,000, June sales of $40,000, July sales of $42,000,

Cash collected in July

= 10% * $42,000 + 75% of 90% * $40,000 + 17% * 90% * $34,000 + 6% * 90% * $30,000

= $4,200 + $27,000 + $5,202  + $1,620

= $38,022

adoni [48]3 years ago
5 0

Answer:

$36,906

Explanation:

The file attached shows a table that explains very well the solution to the problem.

Download docx
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A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by upper c equals 0.
Fantom [35]

Answer:

The cost per month is increasing at a rate $365.

Explanation:

Differentiation Formula

  • \frac{d}{dx}(x^n)= nx^{n-1}  
  • \frac{d}{dx}(a)=0             [ where a is a constant]
  • \frac{d}{dx}(ax^n)=a \frac{d}{dx}(x^n)= anx^{n-1}

Given that,

A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by

c=0.2x^2+10,000.

Again given that,

the rate of changing production is 13 unit per month

i.e \frac{dx}{dt}=13

To find the cost per month, we need to find out the value \frac{dc}{dt} when production is changing at the rate 13 units per month and the production is 70 units.

c=0.2x^2+10,000

Differentiating with respect to t

\frac{d}{dt}(c)=\frac{d}{dt}(0.2x^2)+\frac{d}{dx}(10,000)

\Rightarrow \frac{dc}{dt}=0.2\frac{d}{dt}(x^2)+\frac{d}{dx}(10,000)

\Rightarrow \frac{dc}{dt}=0.2\times 2x^{2-1}\frac{dx}{dt}+0

\Rightarrow \frac{dc}{dt}=0.4x\frac{dx}{dt}

Plugging \frac{dx}{dt}=13

\Rightarrow \frac{dc}{dt}=0.4x\times 13

\Rightarrow \frac{dc}{dt}=5.2x

\frac{dc}{dt}|_{x=70}=5.2\times 70 [ plugging x=70]

            =364

[ The unit of c is not given. Assume that the unit of c is dollar.]

The cost per month is increasing at a rate $365.

4 0
3 years ago
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