The point such that the coordinate is 5;3 is (14, 0)
<h3>Midpoint of coordinates using ratio</h3>
The formula for finding the midpoint of a line in the ratio m:n is expressed as:
M(x, y) = {(mx₁+nx₂)/2, (my₁+ny₂)/2,}
Given the coordinate of G and D on the line as G(5, 0) and D(1,0)
Since there is no y-axis, hence;
x = 5(5)+1(3)/2
x = 25+3/2
x = 28/2
x =14
Hence the point such that the ratio is 5;3 is (14, 0)
Learn more on midpoint of a line here: brainly.com/question/5566419
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The answer is anime and chicken nuggets
Answer:
Step-by-step explanation:
<u>Given equation:</u>
The left side is absolute value, we know it is zero or positive value but never negative.
The right side is negative so the equation can't have solutions as we have contradiction above.
It is different because to find out the answer, change all denominators to 10, since the LCD is 10.
6/10-5/10=1/10
6/10-6/10=0/10
1/10 is not equal to 0/10