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3 years ago

Write a Pythagorean triplet where one member is 6

Mathematics

2 answers:

miss Akunina [59]3 years ago

7 0

Answer:

6 8 10

Step-by-step explanation:

Well, the most known known Pythagorean triplet ever is 3 4 5.

Fortunately, if we scale it by 2:1, we'll get a Pythagorean triplet containing 6.

enyata [817]3 years ago

3 0

Answer:

6,8,10 is the pythagoran triplet

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Pls Help!!!!! I will pick the brainiest answer as well. ;)

denpristay [2]

Answer:

Step-by-step explanation:

20+4=24 24+25=49

6 0

3 years ago

A softball has a diameter of 3.82 inches. How many square inches of material is necessary to cover a softball? Use 3.14 for π

lisabon 2012 [21]

Answer:

45.82 square inches

Step-by-step explanation:

Use the formula for the surface area of a sphere, A = 4 $\pi$ r²

If the diameter is 3.82 inches, the radius is 1.91 inches.

Plug in 3.14 as $\pi$ and 1.91 as r, and solve:

A = 4 $\pi$ r²

A = 4(3.14)(1.91²)

A = 45.82

So, approximately 45.82 square inches of material are needed.

6 0

3 years ago

Explain how you can use addition to find the volume of a composite figure

Charra [1.4K]

Answer:

The volume of a cylinder is the amount of space that will fit inside it. You can use the formula for the volume of a cylinder to find that amount! In this tutorial, see how to use that formula and the radius and height of the cylinder to find the volume. Check it out!

8 0

3 years ago

At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more

I am Lyosha [343]

Answer:

The probability is $P( X \le 4 ) = 0.0054$

Step-by-step explanation:

From the question we are told that

The percentage that are on time is p = 0.76

The sample size is n = 11

Generally the percentage that are not on time is

$q = 1- p$

$q = 1- 0.76$

$q = 0.24$

The probability that no more than 4 of them were on time is mathematically represented as

$P( X \le 4 ) = P(1 ) + P(2) + P(3) + P(4)$

=> $P( X \le 4 ) = \left n } \atop {}} \right.C_1 p^{1} q^{n- 1} + \left n } \atop {}} \right.C_2p^{2} q^{n- 2} + \left n } \atop {}} \right.C_3 p^{3} q^{n- 3} + \left n } \atop {}} \right.C_4 p^{4} q^{n- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{11- 1} + \left 11 } \atop {}} \right.C_2p^{2} q^{11- 2} + \left 11 } \atop {}} \right.C_3 p^{3} q^{11- 3} + \left 11 } \atop {}} \right.C_4 p^{4} q^{11- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{10} + \left 11 } \atop {}} \right.C_2p^{2} q^{9} + \left 11 } \atop {}} \right.C_3 p^{3} q^{8} + \left 11 } \atop {}} \right.C_4 p^{4} q^{7}$

$= \frac{11! }{ 10! 1!} (0.76)^{1} (0.24)^{10} + \frac{11!}{9! 2!} (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!} (0.76)^{3} (0.24)^{8} + \frac{11!}{7!4!} (0.76)^{4} (0.24)^{7}$

$P( X \le 4 ) = 0.0054$

4 0

3 years ago

A is an unknown number when you round a to the nearest thousand you get 21,000 when you round a to the nearest hundred you get 2

beks73 [17]

The unknown number a should be 20,500.

4 0

3 years ago