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vekshin1
3 years ago
11

Write a Pythagorean triplet where one member is 6

Mathematics
2 answers:
miss Akunina [59]3 years ago
7 0

Answer:

6 8 10

Step-by-step explanation:

Well, the most known known Pythagorean triplet ever is 3 4 5.

Fortunately, if we scale it by 2:1, we'll get a Pythagorean triplet containing 6.

enyata [817]3 years ago
3 0

Answer:

6,8,10 is the pythagoran triplet

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2. A triangular pyramid begins with these coordinates:
vagabundo [1.1K]
The rule for the reflection is (x,y,z) → (-x,y,z) so P' = (1, 2, 0) for example. 
<span>Then the rule is (x,y,z) → (x + 2, y + 4, z - 3) so P'' = (3, 6, -3) </span>
3 0
3 years ago
4. A company manufactures tires to meet the annual demand of 125,000 production runs. One production run involves producing 100
lyudmila [28]

Answer:

a) Economic order or production quantity = 2,500 tires.

Number of production runs in a year = 50 runs

Hence, 2,500 tires should be produced in each of the 50 runs in a year to minimize total cost.

b) Minimum total inventory cost = Tsh 30,000

Step-by-step explanation:

The total cost for the tire production firm will be a sum of the total production cost and total inventory cost.

Total cost = Total Production cost + Total inventory cost

Total Production Cost = (Number of production runs in a year) × (Setup Cost of one production run)

Number of production runs in a year = (Annual demand)/(Number of units produced per production run)

Let the annual demand = D

Number of units produced per production run = Q

Setup Cost of one production run = S

Number of production runs in a year = (D/Q)

Total Production Cost = (DS/Q)

Total inventory Cost = (Average inventory level) × (Cost of holding 1 unit in inventory)

Average inventory level is usually assumed to be half of the number of units in a production run = (Q/2)

Cost of Holding a unit of product in inventory = H

Total inventory Cost = (QH/2)

Total cost = TC = (DS/Q) + (QH/2)

At minimum cost, (dTC/dQ) = 0

(dTC/dQ) = -(DS/Q²) + (H/2) = 0

(DS/Q²) = (H/2)

Q² = (2DS/H)

Hence,

Economic order/production quantity = Q = √(2DS/H)

For this question

D = Annual demand = 125,000 tires

S = Setup cost for one production run = Tsh 600

H = Holding cost for one unit in inventory = Tsh 24

Q = √(2×125000×600/24) = 2,500 units

Number of production runs in a year = (D/Q) = (125000/2500) = 50 production runs.

b) Total Inventory Cost = (QH/2)

At minimum total inventory cost, Q = 2,500

Minimum total inventory cost = (2500×24/2) = Tsh 30,000

Hope this Helps!!!

4 0
3 years ago
Simplify: V24 x V12<br> a. 6<br> b. 212<br> c. 28<br> d. 122
Elanso [62]

Answer:

16.97 or approx 17

Step-by-step explanation:

\sqrt{24} = \sqrt{4}\sqrt{6} = 2\sqrt{6}

\sqrt{12} = \sqrt{4}\sqrt{3} = 2\sqrt{3}

2\sqrt{6} · 2\sqrt{3} = 4\sqrt{18} = 4\sqrt{9}\sqrt{2} = 4·3\sqrt{2} = 12\sqrt{2} which is 16.97 or approx 17

3 0
3 years ago
Read 2 more answers
What value of x makes the equation -3+ x = 0 true?<br><br> -3<br> -1/3<br> 1/3<br> 3
Arisa [49]
The value would have x being equal to 3
8 0
3 years ago
Read 2 more answers
A footpath 16 m 80 cm long should be paved with stones 60 cm long. How many stones are needed?​
Annette [7]

Answer:

28 stone bricks are necessary for this footpath.

Step-by-step explanation:

lets start by remembering that 1m has 100cm, therefore 1m = 100cm.

That being said we transform everything to centimeters since the stones are in centimeters.

16 m + 80 cm = 16 × (100 cm) + 80 cm

1600 + 80 = 1680 cm.

If every stone is 60 cm long, we need to divide our footpath length by the stone length to know how many stones are needed, therefore:

1680 cm / 60 cm = 28 bricks!!

I hope it helps :)

5 0
2 years ago
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