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3 years ago

Anyone wanna help please?

Mathematics

2 answers:

maria [59]3 years ago

8 0

Answer:

sure

Step-by-step explanation:

VladimirAG [237]3 years ago

5 0

Answer:

The midpoint cannot be positive

Step-by-step explanation:

A is negative and b is positive. if i am wrong pls report to see if i need improvement i am still a high school too!

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2 Points Which of the following is(are) the solution(s) to . x+6 = 2x - 1?

seropon [69]

Answer:

x = 7

Step by step explanation:

minus x on both sides

6 = x -1

add 1 on both sides

x = 7

7 0

3 years ago

What does the 50th term of this arithmetic sequence: 29,32,35,38

frozen [14]

Answer:

176

Step-by-step explanation:

First term (a) = 29

Common difference (d) = 32 - 29 = 3

For calculating the 50th term , n = 50

Now

$t_{50} = a + ( n - 1) d\\t_{50} = 29 + ( 50 - 1 ) *3\\ t_{50} = 29 + 147\\t_{50} = 176$

hope it will help :)

3 0

2 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

3 0

2 years ago

Find the area please

tatuchka [14]

Answer:

Step-by-step explanation:

Recall that the area of a triangle is given by:

$\displaystyle A = \frac{1}{2} bh$

In this case, the base is x and the height is y. Hence:

$\displaystyle A = \frac{1}{2} xy$

We can write the following ratios:

$\displaystyle \sin \alpha = \frac{x}{12} \text{ and } \cos \alpha = \frac{y}{12}$

Solve for x and y:

$\displaystyle x = 12\sin \alpha \text{ and } y = 12\cos \alpha$

Substitute:

$\displaystyle A = \frac{1}{2}\left(12\sin \alpha\right)\left(12\cos \alpha\right)$

And simplify. Hence:

$\displaystyle A = 72\sin \alpha \cos\alpha$

In conclusion, our answer is D.

6 0

2 years ago

When 0.5 and the number n are multiplied the result is 2.5 what is the value of n

tresset_1 [31]

first form an equation to solve the problem

bring 0.5 over to the other side and divide it by 2.5

the answer is

so,

hope that helps :)

8 0

3 years ago