Let, length and breadth of rectangle is L and B respectively.
It is given that :
The length rectangle is 4 cm more than 3 times the width of the rectangle.
L = 3B + 4 ......1 )
Also, area of square = area of the rectangle + 66
L² = LB + 66
Putting value of L from
L² = ( 3B + 4 )( B ) + 66
L² = 3B² + 4B + 66
( 3B + 4 )² = 3B² + 4B + 66
9B² + 16 + 24B = 3B² + 4B + 66
6B² + 20B - 50 = 0
3B² + 10B - 25 = 0
3B² + 15B - 5B -25 = 0
3B( B + 5 ) -5( B + 5 ) = 0
B = 5/3 units
L = 3( 5/3 ) + 4
L = 5 + 4 = 9 units
Hence, this is the required solution.
Answer:
50.28 inches
Step-by-step explanation:
From the Image, we can find the length of the arc of the semi-circle by dividing the circumference of the resulting circle by 2
Radius= 9in
C= 2πr
C=2*3.142*9
C=2*3.142*9
C= 56.556 inches
Hence the length of the arc is
=56.556/2
=28.278 inches
The perimeter of the shape
=28.278+5+12+5
=50.28 inches
Answer:
I believe it would be A) 2 + m - 1 + - m
If they together at the same rate for the same amount of time, they will solve 48 math problems,
From the question, we can see that two mathletes solve 32 math problems in a certain amount of time, this can be written as:
- 2 mathletes = 32 math problems
In order to determine the number of problems for 3 mathletes, this is expressed as:
DIvide both expressions:
Cross multiply
2x = 3* 32
x = 3 * 16
x = 48math problems
Hence if they together at the same rate for the same amount of time, they will solve 48 math problems,
Learn more on proportion here: brainly.com/question/1496357
