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kolbaska11 [484]
3 years ago
7

A survey was done that asked people to indicate whether they run or ride a bike for exercise.

Mathematics
2 answers:
I am Lyosha [343]3 years ago
5 0
The ratio of the bikers and runners will be 14:1.

Hope that helps!
astra-53 [7]3 years ago
3 0
14 to 1 is your answer.
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A game at the school carnival involves drawing colored marbles out of a bag for a prize. If you draw a red or blue marble, you w
mina [271]
All up there are 20 marbles and only 6 of those are chances of winning so we make it into a fraction 6/20 then times 20 by five to get to 100 (what ever we do to the bottom we do to the top) times 6 by five giving you a fraction of 30/100 then divide 30 by 100 giving you 0.30 ANSWER EQUALS = 0.30
4 0
3 years ago
Anyone help with my homework plz?
iren2701 [21]
Hi!

This is definitely a trapezoid, as it has two equal sides and two inequal sides. It's not a parallelogram, because two sides eventually intersect. It is a quadrilateral, because it has four sides.

None of the others apply here.

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3 0
3 years ago
Barbara buys a box of pens for $4. For every additional box she buys, she gets a $1 discount. Which expression represents the to
Daniel [21]

Answer:

the answer is E !!!!!!!!!!!!!!!!!!!   ; )


5 0
3 years ago
Read 2 more answers
Solve the equation cos (x/2) = cos x + 1. what are the solutions on the interval 0° ≤ x < 360°?
Sedbober [7]

Answer:

Step-by-step explanation:

cos (x/2)=cos x+1

cos (x/2)=2cos ²(x/2)

2 cos²(x/2)-cos (x/2)=0

cos (x/2)[2 cos (x/2)-1]=0

cos (x/2)=0=cos π/2,cos (3π/2)=cos (2nπ+π/2),cos(2nπ+3π/2)

x/2=2nπ+π/2,2nπ+3π/2

x=4nπ+π,4nπ+3π

n=0,1,2,...

x=π,3π

or x=180°,540°,...

180°∈[0,360]

so x=180°

or

2cos(x/2)-1=0

cos (x/2)=1/2=cos60,cos (360-60)=cos 60,cos 300=cos (360n+60),cos (360n+300)

x/2=360n+60,360n+300

x=720n+120,720n+300

n=0,1,2,...

x=120,300,840,1020,...

only 120° and 300° ∈[0,360°]

Hence x=120°,180°,300°

7 0
2 years ago
What is the LCD of the following rational expressions?
Aloiza [94]
\dfrac{x}{x+1} \ , \  \dfrac{7x}{x-1}

\dfrac{x (x -1)}{(x+1)(x -1)} \ , \  \dfrac{7x(x+1)}{(x-1)(x+ 1)}

<u>We know that (a + b)(a - b) = a² - b²:</u>

\dfrac{x (x -1)}{x^2 - 1}} \ , \ \dfrac{7x(x+1)} {x^2 - 1}

Answer: LCD = ( x + 1) (x - 1)
8 0
3 years ago
Read 2 more answers
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