Let
Event A = rolling a 4 on a single die
Event B = rolling a number divisible by 3 (3 or 6) on a single die
There are three outcomes possible in total if either event A happens or event B happens. This is out of six outcomes total.
Divide the values and reduce: 3/6 = 1/2
Final Answer: Choice D) 1/2
P(A|B)<span>P(A intersect B) = 0.2 = P( B intersect A)
</span>A) P(A intersect B) = <span>P(A|B)*P(B)
Replacing the known vallues:
0.2=</span><span>P(A|B)*0.5
Solving for </span><span>P(A|B):
0.2/0.5=</span><span>P(A|B)*0.5/0.5
0.4=</span><span>P(A|B)
</span><span>P(A|B)=0.4
</span>
B) P(B intersect A) = P(B|A)*P(A)
Replacing the known vallues:
0.2=P(B|A)*0.6
Solving for P(B|A):
0.2/0.6=P(B|A)*0.6/0.6
2/6=P(B|A)
1/3=P(B|A)
P(B|A)=1/3
Answer:
27KG
Step-by-step explanation:
Mouse- M , Cat - C, Dog - D
M + C = 10 ----- (1)
M + D = 20 -------(2)
C + D = 24 --------(3)
(1) - (2) => C - D = -10 ---- (4)
(3) + (4) => 2C = 14
=> C = 7
Substitute C in (1) => M + 7 = 10
=> M = 3
Substitute M in (2) => 3 + D = 20
=> D = 17
Therefore C + M + D = 7 + 3 + 17 = 27KG
√81 is farther to the right becaue 2.5^2 = 6.25 and <span>√81 is 9</span>
