Question

There are 38 chocolates in a box, all identically shaped. there are 15 filled with nuts, 10 with caramel, and 13 are solid chocolate. you randomly select one piece, eat it, and then select a second piece. find the probability of selecting 2 solid chocolates in a row.

Answer 1

Total chocolates = 38
Total Solid chocolates = 13

P(2 solid chocolates) = 13/38 x 12/37 = 78/703

---------------------------------------------------------------------------------------------------
Answer: The probability of selecting 2 solid chocolates in a row is 78/703.
---------------------------------------------------------------------------------------------------

Answer 2

The probability of selecting 2 solid chocolates in a row is 0.11

Step-by-step explanation:

Total number of chocolates = 38

Probability of an outcome is the ratio of number of favorable outcome to total number of outcomes.

The probability of selecting 2 solid chocolates in a row = Probability of first piece to be solid chocolate x Probability of second piece to be solid chocolate.

Total number of solid chocolate = 13

$\texttt{Probability of first piece to be solid chocolate = }\frac{13}{38}\\\\\texttt{Probability of second piece to be solid chocolate = }\frac{12}{37}$

$\texttt{The probability of selecting 2 solid chocolates in a row = }\frac{13}{38}\times \frac{12}{37}\\\\\texttt{The probability of selecting 2 solid chocolates in a row = }0.11$

The probability of selecting 2 solid chocolates in a row = 0.11