Question

The zeros of the function f(x)=3x^2-3x-6 are

Answer 1

$3x^2-3x-6=0\\ 3(x^2-x-2)=0\\ x^2-x-2=0 x^2+x-2x-2=0\\ x(x+1)-2(x+1)=0\\ (x-2)(x+1)=0\\ x=2 \vee x=-1$