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Debora [2.8K]
3 years ago
14

The zeros of the function f(x)=3x^2-3x-6 are

Mathematics
1 answer:
Mrac [35]3 years ago
7 0
3x^2-3x-6=0\\
3(x^2-x-2)=0\\
x^2-x-2=0
x^2+x-2x-2=0\\
x(x+1)-2(x+1)=0\\
(x-2)(x+1)=0\\
x=2 \vee x=-1

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