2 years ago

The zeros of the function f(x)=3x^2-3x-6 are

Mathematics

1 answer:

Mrac [35]2 years ago

7 0

$3x^2-3x-6=0\\
3(x^2-x-2)=0\\
x^2-x-2=0
x^2+x-2x-2=0\\
x(x+1)-2(x+1)=0\\
(x-2)(x+1)=0\\
x=2 \vee x=-1
$

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