Question

Solve the following inequalities 7 x minus 5 / 8 x + 3 >4​

Answer 1

Answer:

$x> \frac{8}{51}$

Step-by-step explanation:

$7x - \frac{5}{8} x + 3>4$

Bring constants to one side, simplify:

$\frac{51}{8} x>4 - 3 \\ \frac{51}{8} x>1 \\ x>1 \div \frac{51}{8} \\ x>1 \times \frac{8}{51} \\ x> \frac{8}{51}$

*Note that the inequality sign only changes when you divide the whole inequality by a negative number.

Answer 2

Answer:

$x>\frac{8}{51}$

Step-by-step explanation:

$7x-\frac{5}{8}x+3>4\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\7x-\frac{5}{8}x+3-3>4-3\\\mathrm{Simplify}\\7x-\frac{5}{8}x>1\\\mathrm{Multiply\:both\:sides\:by\:}8\\7x\times \:8-\frac{5}{8}x\times \:8>1\times \:8\\\mathrm{Simplify}\\56x-5x>8\\51x>8\\\mathrm{Divide\:both\:sides\:by\:}51\\\frac{51x}{51}>\frac{8}{51}\\\\x>\frac{8}{51}$

I hope it helps :)