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katen-ka-za [31]

2 years ago

7

A water tank already contains 55 gallons of water when Baxter begins to fill it. Water flows into the tank at a rate of 8 gallon

s per minute. Write a linear equation to model this situation. How long it will take to get 127 gallons of water

1 answer:

Roman55 [17]2 years ago

6 0

Answer: 8x+55=127

Step-by-step explanation: it would take 9 mins because there’s already 55 gallons of water in the tank so you subtract that from 127 which is 72 then you divide 72 by 8 and get 9

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kevin had 13 coins in his pocket. all of his coins are either dimes or quarters. when he emptied his pocket, kevin found that he

Gnesinka [82]

5 quarters and 8 dimes = $2.05

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3 years ago

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The following table shows the probability distribution for a discrete random variable.

mezya [45]

Answer: C. 30.47

Step-by-step explanation:

The mean of discrete random variable i.e. the expected value of X is given by :-

$E(X)=\sum^{i=n}_{i=1} X_iP(X_i)$

Now by using the given table, the expected value of X is given by :-

$\\\\\Rightarrow\ E(X)=23\cdot (0.16)+25\cdot(0.09)+26\cdot(0.18)+31\cdot(0.12)+34\cdot(0.24)+38\cdot(0.21)\\\\\Rightarrow\ E(X)=30.47$

Hence, the mean of discrete random variable= 30.47

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3 years ago

1800 yards per hour is the same rate as which of the following?

m_a_m_a [10]

Answer:

a............ you are welcome

6 0

2 years ago

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Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to chec

klasskru [66]

Answer:

There is a horizontal tangent at (0,-4)

The tangent is vertical at (-2,-3) and (2,-3).

Step-by-step explanation:

The given function is defined parametrically by the equations:

$x=t^3-3t$

and

$y=t^2-4$

The tangent function is given by:

$\frac{dy}{dx}=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$\implies \frac{dy}{dx}=\frac{2t}{3t^2-3}$

The tangent is vertical at when $\frac{dx}{dt}=0$

$\implies \frac{3t^2-3}{2t}=0$

$\implies 3t^2-3=0$

$\implies 3t^2=3$

$\implies t^2=1$

$\implies t=\pm1$

When t=1,

$x=1^3-3(1)=-2$ and $y=1^2-4=-3$

When t=-1,

$x=(-1)^3-3(-1)=2$ and $y=(-1)^2-4=-3$

The tangent is vertical at (-2,-3) and (2,-3).

The tangent is horizontal, when $\frac{dy}{dx}=0$ or $\frac{dy}{dt}=0$

$\implies 2t=0$

$\implies t=0$

When t=0,

$x=0^3-3(0)=0$ and $y=0^2-4=-4$

There is a horizontal tangent at (0,-4)

5 0

2 years ago

Keelie has a triangular-shaped card. The lengths of its sides are 5.1 cm, 6.8 cm, and 8.5 cm. Is the card a right triangle?

anastassius [24]

Answer:

Yes

Step-by-step explanation:

To figure out if a triangle is a right triangle, you have to plug in the side lengths into the equation $a^{2}$ + $b^{2}$ = $c^{2}$

Your equation should look like $5.1^{2} + 6.8^{2} = 8.5^{2}$

Now you simplify. The equation should be: 26.01 + 46.24 = 72.25

Then add 26.01 and 46.24 to get 72.25 = 72.25

Since they are equal, the triangle is a right triangle.

8 0

3 years ago

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