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Sedaia [141]
2 years ago
7

Which segment does NOT intersect line AG? Please help.​

Mathematics
1 answer:
Lina20 [59]2 years ago
4 0

Answer:

line BC

Step-by-step explanation:

Line BC is the only line that doesn’t touch line AG

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harina [27]
A)
x=sales

4/100 x + 400≥460

b)
Solve the inequation:
4/100 x+400≥460
lest common multiple= 100
4x+40000≥46000
4x≥46000-40000
4x≥6000
x≥6000/4
x≥1500

answer: the minimun amount tha se will needs to sell  is $1500. 
7 0
3 years ago
This​ week, 951 people went to the beach. Last​ week, 1,173 people went to the beach. The number of people who went to the beach
Ugo [173]
It fell by 19%
Use 1173 as your total and then find the percent from 951 and subtract from 100 and that’s the percent that fell
4 0
3 years ago
Ed and his family went on a backpacking trip. They started hiking at 3:35 P.M. It took 3 hours and 15 minutes to reach their cam
Veronika [31]

Answer: 8:15 P.M.

Step-by-step explanation: 3:35 plus a total of 4 hours and 40 minutes

3:35 --- 7:35 ( +4 hours )

7:35 --- 8:15 ( +40 minutes )

5 0
3 years ago
Line J M is the perpendicular bisector of LK.
drek231 [11]

Answer:

The congruent segments are LN and NK ⇒ C

Step-by-step explanation:

<em>If a line is a perpendicular bisector of another line, that means this line intersects the other line in its midpoint and form right angles around this point</em>

∵ Line JM is the perpendicular bisector of line LK

→ That means JM intersect LK at the midpoint of LK

∵ Line JM intersects line LK at point N

∴ Point N is the midpoint of LK

∵ N divides LK into two segments LN and NK

∵ N is the midpoint of LK

→ That means LN equals NK

∴ LN = NK

∴ The congruent segments are LN and NK

5 0
3 years ago
Question 5 (5 points)
Tpy6a [65]

Answer:

The solution of the system of equations is, (1,-1,2)

Step-by-step explanation:

Given system equation;

x + 5y - 3z = -10

-5x + 6y – 5z = -21

-x + 8y - 8z = -25

Matrix form is written as;

\left[\begin{array}{ccc}1&5&-3\\-5&6&-5\\-1&8&-8\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}-10\\-21\\-25\end{array}\right] \\\\\\det. = 1\left[\begin{array}{cc}\\6&-5\\8&-8\end{array}\right] -5\left[\begin{array}{cc}\\-5&-5\\-1&-8\end{array}\right] -3\left[\begin{array}{cc}\\-5&6\\-1&8\end{array}\right] \\\\\\det. = 1(-8) -5(35)-3(-34)= -8 - 175+ 102 = -81

Cofactor;

First \ row \left[\begin{array}{cc}+\\ 6&-5\\\ 8&-8\end{array}\right  \left\begin{array}{cc}-\\ -5&-5\\-1&-8\end{array}\right \left\begin{array}{cc}+\\-5&6\\-1&8\end{array}\right] = [-8  \ \ -35 \ \ -34]\\\\\\\ Second \ row \left[\begin{array}{cc}-\\ 5&-3\\\ 8&-8\end{array}\right  \left\begin{array}{cc}+\\ 1&-3\\-1&-8\end{array}\right \left\begin{array}{cc}-\\1&5\\-1&8\end{array}\right]  = [16\ \ -11 \ \ -13]\\\\\\

Third \ row \left[\begin{array}{cc}+\\ 5&-3\\\ 6&-5\end{array}\right  \left\begin{array}{cc}-\\ 1&-3\\-5&-5\end{array}\right \left\begin{array}{cc}+\\1&5\\-5&6\end{array}\right]= [-7 \  \ 20\ \ 31]

Cofactor = \left[\begin{array}{ccc}-8&-35&-34\\16&-11&-13\\-7&20&31\end{array}\right]

inverse \ matrix =-\frac{1}{81}  \left[\begin{array}{ccc}-8&16&-7\\-35&-11&20\\-34&-13&31\end{array}\right] \\\\\\

Solution of the matrix:

\left[\begin{array}{c}x\\y\\z\end{array}\right] = -\frac{1}{81}  \left[\begin{array}{ccc}-8&16&-7\\-35&-11&20\\-34&-13&31\end{array}\right]  X \left[\begin{array}{c}-10\\-21\\-25\end{array}\right] = \left[\begin{array}{c}\frac{-8*-10 }{-81 } +\frac{16*-21 }{-81 } + \frac{-7*-25 }{-81 }\\\\\frac{-35*-10 }{-81 } +\frac{-11*-21 }{-81 }+ \frac{20*-25 }{-81 }\\\\\frac{-34*-10 }{-81 }+ \frac{-13*-21 }{-81 }+ \frac{31*-25 }{-81 }\end{array}\right] \\\\\

\left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}\frac{-81}{-81} \\\\\frac{81}{-81} \\\\\frac{-162}{-81} \end{array}\right] =  \left[\begin{array}{c}1\\-1\\2\end{array}\right]

Therefore, the correct option is (1,-1,2)

5 0
3 years ago
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