Answer:
They are the first trophic level in an ecosystem and without them the rest of the organisms in the ecosystem would have no source of energy
Explanation:
The autotrophs are the producers in the ecosystem. They manage to produce food for themselves, and they represent the first trophic level, thus they are the basis of any ecosystem. These organisms are the once that produce the energy, and the organisms in the trophic levels above them use their energy to survive. If the autotrophs are removed from and ecosystem, the ecosystem will collapse, as there will be no source of energy for the organisms in the trophic levels above, thus all of them will die out quickly.
Answer:
Nombrado como la formación media del grupo La Plata para Todilto Park, T20N, R20W, McKinley Co, NM en la cuenca de San Juan. No se ha designado ninguna localidad tipo. Tapas de piedra arenisca Wingate. Es más antiguo que la piedra arenisca de Navajo. Varía de 2 a 200 pies de espesor. Dos secciones medidas. Mapa geológico. Mapeado en Apache contiguo y Navajo Cos, AZ en la cuenca de Black Mesa. Consiste en piedra caliza azul grisácea, densa y resistente cubierta y sustentada por arenisca calcárea blanca en una localidad de Apache Co, y de conglomerado de piedra caliza separada por lutitas calcáreas y lechos de arenisca en Navajo Co. El contacto de Navajo-Todilto suele conformarse. Fragmentos bien gastados de sílex negro, gris y blanco que se encuentran cerca de la parte superior en cantidades suficientes para formar bandas irregulares incrustadas en la piedra caliza. La parte media de La Plata (¿Todilto?) Se engrosa hacia el norte y se encuentran cambios en esa más arenisca y pizarra. Huellas de dinosaurios encontradas en dos localidades. Asignado a Jurassic.
Explanation:
Answer:
Correct Answer is C 99% positive
Explanation: Hope This Helps:)
Answer:
Explanation:
Bacterial count in stock- 1.85x10^6 cfu/ml
Dilution methods
Take 100 uL or (0.1ml) from stock and add to 900ul (0.9ml) saline and mixed it- this makes 10^1dilution.
Now take 100ul from 10^1 dilution and add to next 900ul saline this is 10^2 dilution, similarly do upto 10^5 dilution.
Then take 100ul from 10^ 4 and 10^5 dilution seperately and plate on LB agar plate seperetely and count the colonies.
Cfu/ml formula= (No.of colonies x dilution factor)/0.1 ml
So suppose, 18 colonies formed on 10^4 dilution then total no. Of cells in stock will be 18x10^4/ 0.1= 18x10^5 cfu/ml.
If we dilute 10^4 or 10^5 that's leads to colony count of 18-19 colonies on 10^4 dilution while 2 colonies should come on plate of 10^5 dilution.
Answer:
cut it into two
marinate it
rest it for 2 hours
barbeque it in an Australian barbecue