Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:

The amount of deer that were initally in the reserve corresponds to the value of N when t=0


A. Initially, there were 12 deer.
B. 
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. 
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
I solved and the mean is 10
<em>zero product property (Angela)</em>
- Step-by-step explanation:
<em>Hi there ! </em>
<em> (Angela)</em>
<em>3x² + 10x = 0</em>
<em>x(3x + 10) = 0</em>
<em>x = 0 => x₁ = 0</em>
<em>3x + 10 = 0 => 3x = - 10 => x₂ = - 10/3 = - 3 1/3</em>
<em>Good luck !</em>
Answer:
A.
Step-by-step explanation:
Hope this helps and have a great day!!!!
Solution:

As one of the fraction is a proper fraction and another one is Mixed fraction.
There are two methods of solving it.
1. 
2.
→→Here i have used Distributive property with respect to addition and Subtraction i.e a×(b+c)= a ×b + a×c or a×(b-c)=a×b-a×c
Now, you can fill the blanks by yourself.