A tree cast a shadow of 30m long and a 2m stick casts one that is 3m long. As show in the below diagram how tall is the tree?
2 answers:
Answer:
Step-by-step explanation:
<u>We have similar triangles here.</u>
- BC║DE, AB║AD and AC║AE ⇒ ΔADE ~ ΔABC
<u>The ratio of corresponding sides of similar triangles is same:</u>
- BC/DE = AC/AE
- BC / 2 = 30/3
- BC / 2 = 10
- BC = 2*10
- BC = 20 m
Take the similar triangles,
→ ∆ADE ≈ ∆ABC
Now we can find,
The height of the tree in meters,
→ BC/DE = AC/AE
In this equation BC is the height of tree,
→ BC/2 = 30/3
→ BC/2 = 10
→ BC = 10 × 2
→ BC = 20
Hence, the height of the tree is 20 m.
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Answer:
(6.3*10³) ÷ (1.8*10⁵)
6.3*10³ = 0.063*10⁵
then:
(6,3*10³) ÷ (1.8*10⁵) = (0.063*10⁵) ÷ (1.8*10⁵)
= 0.063/1.8
= 0.035
0.035 = 3.5 *10⁻² = 35*10⁻³
