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Gnoma [55]
3 years ago
15

A tree cast a shadow of 30m long and a 2m stick casts one that is 3m long. As show in the below diagram how tall is the tree?​

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
6 0

Answer:

  • 20 m

Step-by-step explanation:

<u>We have similar triangles here.</u>

  • BC║DE, AB║AD and AC║AE ⇒ ΔADE ~ ΔABC

<u>The ratio of corresponding sides of similar triangles is same:</u>

  • BC/DE = AC/AE
  • BC / 2 = 30/3
  • BC / 2 = 10
  • BC = 2*10
  • BC = 20 m
Kay [80]3 years ago
4 0

Take the similar triangles,

→ ∆ADE ≈ ∆ABC

Now we can find,

The height of the tree in meters,

→ BC/DE = AC/AE

In this equation BC is the height of tree,

→ BC/2 = 30/3

→ BC/2 = 10

→ BC = 10 × 2

→ BC = 20

Hence, the height of the tree is 20 m.

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Answer:

<u>Question 1:</u>

<u>(a) </u>P(x<60) = 0.9236

<u>(b) </u>P(x>16) = 0.9564

<u>(c) </u>P(16<x<60) = 0.88

<u>(d) </u>P (x>60) = 0.0764

<u />

<u>Question 2:</u>

<u>(a) </u>P(x<3) = 0.0668

<u>(b) </u>P(x>7) = 0.0062

<u>(c) </u>P(3<x<7) = 0.927

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Step-by-step explanation:

<u>Question 1:</u>

x = no. of mg of porphyrin per deciliter of blood.

μ = 40

σ = 14

(a) We need to compute P(x<60). We need to find the z-score using the normal distribution formula:

z = (x - μ)/σ

P(x<60) = P((x - μ)/σ < (60 - 40)/14)

             = P(z < 20/14)

             = P(z<1.43)

Using the normal distribution probability table we can find the value of p at z=1.43.

P(z<1.43) = 0.9236

so, P(x<60) = 0.9236

(b) P(x>16) = P(z>(16-40)/14)

                 = P(z>-1.71)

                 = 1 - P(z<-1.71)

                 = 1 - 0.0436

    P(x>16) = 0.9564

(c) P(16<x<60) = P((16-40)/14) < x < (60-40)/14)

                        = P(-1.71 < z < 1.43)

This probability can be calculated as: P(z<1.43) - P(z<-1.71)

                                         P(16<x<60) = 0.9236 - 0.0436

                                         P(16<x<60) = 0.88

(d) P(x>60) = 1 - P(x<60)

     we have calculated P(x<60) in part (a) so,

    P(x>60) = 1 - 0.9236

    P (x>60) = 0.0764

<u>Question 2:</u>                              

μ = 4.5 mm

σ = 1.0 mm

In this question, we will again compute the z-scores and then find the probability from the normal distribution table.

(a) P(x<3) = P(z<(3-4.5)/1)

                = P(z<-1.5)

     P(x<3) = 0.0668

(b) P(x>7) = 1 - P(x<7)

               = 1 - P(z<(7-4.5)/1)

               = 1 - P(z<2.5)

               = 1 - 0.9938

    P(x>7) = 0.0062

(c) P(3<x<7) = P(x<7) - P(x<3)

  we have computed both of these probabilities in parts (a) and (b) so,

    P(3<x<7) = 0.9938 - 0.0668

    P(3<x<7) = 0.927

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Answer:

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We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.

Since we know that an exponential function is in form: y=a*b^x, where,

a = Initial value,

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Let us convert our given decay rate in decimal form.

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Let us find x by subtracting 2010 from 2019.

x=2019-2010=9

Upon substituting x=9 in our function we will get,

y=14,000*(0.94)^9

y=14,000*0.5729948022286167

y=8021.927\approx 8022

Therefore, the population of fish in 2019 will be 8022.

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