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Effectus [21]
2 years ago
7

CD is a line parallel to AB and passes through the point (3, 5).

Mathematics
1 answer:
Mrac [35]2 years ago
4 0

Answer:

y=5/3x+b

Step-by-step explanation:

Supposing CD uses the equation y=mb (meaning CD passes through the origin) and passes through (3,5), we then know the slope if 5/3 and the y intercept is 0. We can then write CD's equation as y=5/3x+0, or just y=5/3x.

So if AB is parallel to CB, then their equation is y=5/3x+b, as we don't the y-intercept yet.

Thank you!

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Expresss 8 2/7 as a %
Darya [45]

828.57%

Step-by-step explanation:

8 0
3 years ago
Find (4/5+3/6-5/12) ÷ 2/3​
slavikrds [6]

Answer:

1/2 + 2/3 + 5/4 = 29/ 12 = 2 5/  12  ≅ 2.4166667

Step-by-step explanation:

Add: 1/ 2  + 2/ 3  = 1 · 3/ 2 · 3  + 2 · 2/ 3 · 2  = 3/ 6  + 4/ 6  = 3 + 4/ 6  = 7/ 6

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(2, 3) = 6. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 2 × 3 = 6. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - one half plus two thirds = seven sixths.

Add: the result of step No. 1 + 5/ 4  = 7/ 6  + 5/ 4  = 7 · 2/ 6 · 2  + 5 · 3/ 4 · 3  = 14/ 12  + 15/ 12  = 14 + 15/ 12 = 29/ 12

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(6, 4) = 12. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 6 × 4 = 24. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - seven sixths plus five quarters = twenty-nine twelfths.

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

7 0
3 years ago
22.
Vlada [557]

Step-by-step explanation:

\sqrt{p}  =  \sqrt[r]{w -  {as}^{2} }

Find raise each side of the expression to the power of r

That's

<h2>( \sqrt{p} )^{r}  =  (\sqrt[r]{w -  {as}^{2} } ) ^{r}</h2>

we have

<h2>( \sqrt{p} )^{r}  =  w -  {as}^{2}</h2>

Send w to the left of the equation

<h2>( \sqrt{p} )^{r}  - w =  -{as}^{2}</h2>

Divide both sides by - a

We have

<h2>{s}^{2}  =  -\frac{( \sqrt{p} )^{r}  - w}{a}</h2>

Find the square root of both sides

We have the final answer as

<h2>s =  \sqrt{ -\frac{( \sqrt{p} )^{r} - w }{a} } </h2>

Hope this helps you

3 0
3 years ago
Two sides of a triangle have lengths 11 and 18. Write an inequality to represent the possible lengths for the third side, x.
KatRina [158]
<span>Side inequality of triangle states that the sum of any two sides of a triangle should be greater than the third side so the sum of two sides

In this case, 11 + 18 = 29 > 3rd side So 29 > 3rd side or we can say 3rd side < 29

Also, the third side cannot be smaller than the difference of the given two sides so the third side has to be greater than 18-11 = 7 so 3rd side > 7 so if length of 3rd side is represented by x, then 7 < x < 29</span>
3 0
3 years ago
Read 2 more answers
Which statement regarding the diagram is true?
Semmy [17]

Answer:

mKML+mMLK=mJKM

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. Types of triangles are scalene, acute, obtuse, equilateral, isosceles, and right triangle.

As shown in the diagram, polygon MLK is a triangle. The sum of angles in a triangle is equal to 180°, hence:

m∠MLK + m∠KML + m∠MKL = 180° (sum of angles in a triangle).

m∠MKL = 180 -  (m∠MLK + m∠KML)      (1)

Also along line JL, the sum of angles on one side of a straight line is 180°, therefore:

m∠JKM + m∠MKL = 180° (sum of angles in a straight line)

m∠JKM + m∠MKL = 180°                (2)

From equations 1 and 2, equating give:

m∠JKM + [180 -  (m∠MLK + m∠KML)) =  180

m∠JKM + 180 - m∠MLK - m∠KML =  180

m∠JKM = m∠MLK + m∠KML

4 0
3 years ago
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