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Effectus [21]
2 years ago
7

CD is a line parallel to AB and passes through the point (3, 5).

Mathematics
1 answer:
Mrac [35]2 years ago
4 0

Answer:

y=5/3x+b

Step-by-step explanation:

Supposing CD uses the equation y=mb (meaning CD passes through the origin) and passes through (3,5), we then know the slope if 5/3 and the y intercept is 0. We can then write CD's equation as y=5/3x+0, or just y=5/3x.

So if AB is parallel to CB, then their equation is y=5/3x+b, as we don't the y-intercept yet.

Thank you!

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Jane has 6 red marbles. 4 green marbles, and 2 black marbles in a bag. What is the probability of ramdomly pulling out a green m
fomenos

the total number of marbles in the bag is 12 . so the probability of getting a green marble at random is 4/12 which resluts to 1/3

4 0
3 years ago
Drew jumped farther than all 4 students above but jumped shorter than 7 feet , 7 inches. How far could drew have jumped? Write s
S_A_V [24]
<h3>The distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft  6 inches.</h3>

Step-by-step explanation:

Here, the needed table is attached for the reference.

Now, as we can see from the table:

The distance covered by  Cindy  = 2 yards, 1 foot 3 inches

The distance covered by  Tyrette   =  7 feet, 2 inches

The distance covered by Nina   =   2 yards, 1 foot, 1 inch

The distance covered by  Monique   = 7 feet, 4 inches

As we know : 1 yard  =  3 feet

So, the distance covered  by :

Cindy  =  2 yards, 1 foot 3 inches = 3 ft x (2)  + 1 ft +  3 in  = 7 ft 3 in

Tyrette   =  7 feet, 2 inches

Nina   =   2 yards, 1 foot, 1 inch  = = 3 ft x (2)  + 1 ft +  1 in  = 7 ft 1 in

Monique   = 7 feet, 4 inches

So by comparing all distances, we can see that:

The maximum distances jumped by all four  is 7 ft 4 inches.

The distance covered by Drew is less than 7 ft 7 in.

So, he must have jumped 7 ft 5 inches OR 7 ft  6 inches.

Hence, the distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft  6 inches.

4 0
3 years ago
A regular octagon has a radius of 6 ft and a side length of
Svetlanka [38]

Answer:

<h2>Area of the regular octagon is approximately 102ft²</h2>

Step-by-step explanation:

Given the radius and length of a side of regular octagon as shown;

radius = 6ft and length of side = 4.6ft

Area of a regular octagon is expressed as A = 2(1+\sqrt{2} )a^{2} where a is the length of one side. Given a = 4.6ft

Area = A = 2(1+\sqrt{2} )(4.6)^{2}\\

= 2(1+\sqrt{2} )*21.16\\= (2+2\sqrt{2})*21.16\\ = 4.83*21.16\\= 102.20ft^{2} \\

Area of the regular octagon is approximately 102ft²

3 0
3 years ago
Which segment is opposite to angle D? DС FC or DF ​
PIT_PIT [208]

Answer:

The segment opposite to angle D is CF.

Step-by-step explanation:

To find what angle is opposite to a side. All you just have to do is see which segment doesn't touch that angle.  We see that angle D does not touch CF, so angle D must be opposite to CF.

6 0
2 years ago
Use the distributive property to simplify 4^x(2^-6)
julsineya [31]
Is it 4 times x or 4 to the power of x, if the first one then, 8x-24x. if the second then 8^-6x
6 0
3 years ago
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