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Mkey [24]
3 years ago
15

Luke began redding his Lego

Mathematics
1 answer:
Ray Of Light [21]3 years ago
6 0
Reading* read* stop* and it’s 3:31
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An open box is made from a 20 cm x 3 cm piece of tin by cutting a square from each corner and folding up the edges. The area of
Marta_Voda [28]

Answer:

Length of the final sides: 6 cm and 16 cm

Step-by-step explanation:

The lengths of the sides of the original box are

L=20 cm\\W=10 cm

Later, a piece of tin is cut out from each corner; the piece cut out has the shape of the square: we can call the length of its generic side x. Therefore, the dimensions of the box will now be:

L'=L-2x\\W'=W-2x

We also know that the area is

A=96 cm^2

And the area can be written as product of length and width, therefore:

A=L'W'

So we find:

A=(L-2x)(W-2x)\\96=(20-2x)(10-2x)

Solving for x,

96=200-20x-40x+4x^2\\4x^2-60x+104=0\\\\x^2-15x-26=0

Which has two solutions:

x = 13 cm (this is larger than the initial length of the width, therefore we discard it)

x = 2 cm

So, the length of the new sides are

L=20-2x=20-2(2)=16 cm\\W=10-2x=10-2(2)=6 cm

7 0
3 years ago
0.25x2 -0.25x - 10.5 = 0<br><br>​
Tpy6a [65]

x=7 or x=-6

Let's solve your equation step-by-step.

0.25x2−0.25x−10.5=0

For this equation: a=0.25, b=-0.25, c=-10.5

0.25x2+−0.25x+−10.5=0

Step 1: Use quadratic formula with a=0.25, b=-0.25, c=-10.5.

x=

−b±√b2−4ac

2a

x=

−(−0.25)±√(−0.25)2−4(0.25)(−10.5)

2(0.25)

x=

0.25±√10.5625

0.5

x=7,−6

6 0
3 years ago
What is the answer <br><br> I will give you 14 points
IceJOKER [234]

5/6+(-1 1/6) = 5/6-7/6 = -2/6 = -1/3

answer: Put the sum 2 marks to the left of 0 (to place -1/3).

7 0
4 years ago
Help on the last one
Cerrena [4.2K]

Answer:hector has 6 and Jill has 3 and all together is 9

Step-by-step explanation:

6 0
3 years ago
Which zero pair could be added to the function f(x)=x2 +12x+6 so that the function can be written in vertex form
Gnom [1K]

The most general proccedure for this type of problems is the following:

For a quadratic function of the following form f(x)=x^2+bx+c; where b and c are real numbers.

1) Identify the value that accompanies the x, that is, the value "b"

2) Divide the value of b by 2 and then square it: (\frac{b}{2})^2

3) Add and subtract in the function the value of  (\frac{b}{2})^2

4) Write the complete function of the form f(x) = (x+\frac{b}{2})^2-(\frac{b}{2} )^2+c

For the function presented f(x)=x^2 +12x+6 the result is as follows:

1) The value of b is 12

2) (\frac{12}{2} )^2=36

3) f(x)=(x^2+12x+36)-36+6

4)f(x)=(x+6)^2-36+6

Finally the function is:

f(x)=(x + 6)^2-30


The zero pair that must be added is 36 and -36


3 0
3 years ago
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