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dusya [7]
3 years ago
7

0.25x2 -0.25x - 10.5 = 0​

Mathematics
1 answer:
Tpy6a [65]3 years ago
6 0

x=7 or x=-6

Let's solve your equation step-by-step.

0.25x2−0.25x−10.5=0

For this equation: a=0.25, b=-0.25, c=-10.5

0.25x2+−0.25x+−10.5=0

Step 1: Use quadratic formula with a=0.25, b=-0.25, c=-10.5.

x=

−b±√b2−4ac

2a

x=

−(−0.25)±√(−0.25)2−4(0.25)(−10.5)

2(0.25)

x=

0.25±√10.5625

0.5

x=7,−6

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Answer:

no

Step-by-step explanation:

the answer is no because the quantum formula states that a quantum state is a mathematical entity that provides a probability distribution for the outcomes of each possible measurement on a system. Quantum states that cannot be written as a mixture of other states are called pure quantum states, while all other states are called mixed quantum states.

4 0
3 years ago
Multiply -90/11 by -55/72 with explanation...
vladimir2022 [97]

Answer:

25/4

Step-by-step explanation:

Multiplying numerators gives 4950 and multiplying denominators gives 792. 4950/792. simplify to get simplest form as 25/4

4 0
3 years ago
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I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
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nika2105 [10]
Where is the question??
5 0
3 years ago
1. The total area within any continuous probability distribution is equal to 1.00.
olchik [2.2K]

Answer:

1. True

2. False.

3. True.

Step-by-step explanation:

1. The total area within any continuous probability distribution is equal to 1.00: it is true because the maximum probability (value) is one (1), therefore, the total (maximum) area is also one (1).

<em>Hence, for continuous probability distribution: probability = area</em>.

2. For any continuous probability distribution, the probability, P(x), of any value of the random variable, X, can be computed: False because it has an infinite number of possible values, which can not be counted or uncountable.

<em>Hence, it cannot be computed. </em>

3. For any discrete probability distribution, the probability, P(x), of any value of the random variable, X, can be computed: True because it has a finite number of possible values, which are countable or can be counted.

<em>Hence, it can be computed. </em>

5 0
3 years ago
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