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dusya [7]
3 years ago
7

0.25x2 -0.25x - 10.5 = 0​

Mathematics
1 answer:
Tpy6a [65]3 years ago
6 0

x=7 or x=-6

Let's solve your equation step-by-step.

0.25x2−0.25x−10.5=0

For this equation: a=0.25, b=-0.25, c=-10.5

0.25x2+−0.25x+−10.5=0

Step 1: Use quadratic formula with a=0.25, b=-0.25, c=-10.5.

x=

−b±√b2−4ac

2a

x=

−(−0.25)±√(−0.25)2−4(0.25)(−10.5)

2(0.25)

x=

0.25±√10.5625

0.5

x=7,−6

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State the horizontal asymptote of the rational function. f(x) = quantity x squared plus three x minus two divided by quantity x
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f(x)=\dfrac{x^2+3x-2}{x-2}\\ D_f=\mathbb{R}\setminus\{2\}\\\\ \displaystyle \lim_{x\to \infty}\dfrac{x^2+3x-2}{x-2}=\lim_{x\to \infty}\dfrac{x\left(x+3-\dfrac{2}{x}\right)}{x\left(1-\dfrac{2}{x}\right)}=\lim_{x\to \infty}\dfrac{x+3-\dfrac{2}{x}}{1-\dfrac{2}{x}}=\dfrac{\infty}{1}=\infty\\ \lim_{x\to -\infty}\dfrac{x^2+3x-2}{x-2}=\lim_{x\to -\infty}\dfrac{x\left(x+3-\dfrac{2}{x}\right)}{x\left(1-\dfrac{2}{x}\right)}=\lim_{x\to -\infty}\dfrac{x+3-\dfrac{2}{x}}{1-\dfrac{2}{x}}=\dfrac{-\infty}{1}=-\infty

The limits are not numbers, so the asymptote doesn't exist.

8 0
3 years ago
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4 years ago
Can't figure out please help<br> Find m∠N in the parallelogram.
Aliun [14]

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8 0
3 years ago
What single decimal multiplier would you use to decrease by 3% followed by a 6% increase?
Charra [1.4K]

Answer:

1.0282

Step-by-step explanation:

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6 0
3 years ago
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