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Bogdan [553]
3 years ago
5

Which professionals can benefit from an understanding of statistics? Check all of the boxes that apply. magician trying to locat

e the most popular place to put on magic shows software developer who needs the most compatible programming language director of education who wants to know the school district’s average scores on national standardized tests
Computers and Technology
2 answers:
mojhsa [17]3 years ago
8 0

Answer:

All 3 of them

Explanation:

Ray Of Light [21]3 years ago
6 0

Answer:

all of them because i did the quiz and got it right

Explanation:

You might be interested in
Which of the following is a quick way to restore the arrow pointer after you have used it for drawing?
Oxana [17]
A quick way to restore the arrow pointer after you have used it for drawing is to press the esc key.  The esc key is <span>used for any of the different </span>functions<span>, as to interrupt or cancel the current process or running program, or to close a pop-up window.</span>
7 0
3 years ago
Indicate the order that the three files will be processed <br><br> Please answer
defon
The answer is 10 because I looked it up
6 0
4 years ago
Write a program which:
Studentka2010 [4]

Answer:

Ill do this in C# and Java

Explanation:

C#:

public static void Main(string[] args)

       {

           string input = Console.ReadLine();

               switch (input)

               {

                   case "A1":

                       Console.WriteLine("Footwear:");

                       Console.WriteLine("Shoes");

                       break;

                   case "B1":

                       Console.WriteLine("Tops:");

                       Console.WriteLine("Jackets");

                       break;

                   case "C1":

                       Console.WriteLine("Pants:");

                       Console.WriteLine("Trousers");

                       break;

                   case "A2":

                       Console.WriteLine("Footwear:");

                       Console.WriteLine("Trainers");

                       break;

                   case "B2":

                       Console.WriteLine("Tops:");

                       Console.WriteLine("TShirts");

                       break;

                   case "C2":

                       Console.WriteLine("Pants:");

                       Console.WriteLine("Shorts");

                       break;

                   default:

                       Console.WriteLine("Incorrect Input");

                       break;

               }

       }

Java:

public static void main(String[] args)

   {

       Scanner myObj = new Scanner(System.in);  // Create a Scanner object

       String input = myObj.nextLine();

       {

           switch (input)

               {

                   case "A1":

                       System.out.println("Footwear:");

                       System.out.println("Shoes");

                       break;

                   case "B1":

                       System.out.println("Tops:");

                       System.out.println("Jackets");

                       break;

                   case "C1":

                       System.out.println("Pants:");

                       System.out.println("Trousers");

                       break;

                   case "A2":

                       System.out.println("Footwear:");

                       System.out.println("Trainers");

                       break;

                   case "B2":

                       System.out.println("Tops:");

                       System.out.println("TShirts");

                       break;

                   case "C2":

                       System.out.println("Pants:");

                       System.out.println("Shorts");

                       break;

                   default:

                       System.out.println("Incorrect Input");

                       break;

               }

       }

3 0
4 years ago
Implement a method called bubbleSort, that takes an ArrayList, sorts it using bubble sort algorithm, and returns a sorted list;
boyakko [2]

Answer:

Java algorithm is given below

Explanation:

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Random;

public class Temp {

   static void bubbleSort(ArrayList<Integer> list) {

       int n = list.size();

       for (int p = 0; p < n - 1; p++)

           for (int q = 0; q < n - p - 1; q++)

               if (list.get(q) > list.get(q + 1)) {

                   int temp = list.get(q);

                   list.set(q, list.get(q + 1));

                   list.set(q + 1, temp);

               }

   }

   static void selectionSort(ArrayList<Integer> list) {

       int n = list.size();

       for (int p = 0; p < n - 1; p++) {

           int minimumIndex = p;

           for (int q = p + 1; q < n; q++)

               if (list.get(q) < list.get(minimumIndex))

                   minimumIndex = q;

           int temp = list.get(p);

           list.set(p, list.get(minimumIndex));

           list.set(minimumIndex, temp);

       }

   }

   static void insertionSort(ArrayList<Integer> list) {

       int size = list.size();

       int p, val, q;

       for (p = 1; p < size; p++) {

           val = list.get(p);

           q = p - 1;

           while (q >= 0 && list.get(q) > val) {

               list.set(q + 1, list.get(q));

               q = q - 1;

           }

           list.set(q + 1, val);

       }

   }

   static void mergeSort(ArrayList<Integer> list, int low, int high) {

       if (low < high && (high - low) >= 1) {

           int mid = (high + low) / 2;

           mergeSort(list, low, mid);

           mergeSort(list, mid + 1, high);

           merger(list, low, mid, high);

       }

   }

   static void merger(ArrayList<Integer> list, int low, int mid, int high) {

       ArrayList<Integer> mergedArray = new ArrayList<Integer>();

       int left = low;

       int right = mid + 1;

       while (left <= mid && right <= high) {

           if (list.get(left) <= list.get(right)) {

               mergedArray.add(list.get(left));

               left++;

           } else {

               mergedArray.add(list.get(right));

               right++;

           }

       }

       while (left <= mid) {

           mergedArray.add(list.get(left));

           left++;

       }

       while (right <= high) {

           mergedArray.add(list.get(right));

           right++;

       }

       int i = 0;

       int j = low;

       while (i < mergedArray.size()) {

           list.set(j, mergedArray.get(i++));

           j++;

       }

   }

   public static void main(String[] args) throws Exception {

       ArrayList<Integer> list = new ArrayList<>();

       Random rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       long start = System.currentTimeMillis();

       selectionSort(list);

       int sel = (int) (System.currentTimeMillis() - start);

       System.out.println("Selection Sort time (in ms): " + sel);

       list.clear();

       // ------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       insertionSort(list);

       int ins = (int) (System.currentTimeMillis() - start);

       System.out.println("Insertion Sort time (in ms): " + ins);

       list.clear();

       // ------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       bubbleSort(list);

       int bub = (int) (System.currentTimeMillis() - start);

       System.out.println("Bubble Sort time (in ms): " + bub);

       list.clear();

       // ---------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       mergeSort(list, 0, list.size() - 1);

       int mer = (int) (System.currentTimeMillis() - start);

       System.out.println("Merge Sort time (in ms): " + mer);

       long m = Math.min(Math.min(sel, ins), Math.min(bub, mer));

       if (m == sel)

           System.out.println("Selection Sort is fastest");

       else if (m == ins)

           System.out.println("insertion Sort is fastest");

       else if (mer == m)

           System.out.println("Merge Sort is fastest");

       else if (m == bub)

           System.out.println("Bubble Sort is fastest");

   }

}

6 0
3 years ago
Assume you have 100 values that are all different, and use equal width discretization with 10 bins.
zepelin [54]

Answer:

a) 10

b) 1

C) 10

D) 1

E) 20

F)  10

Explanation:

a) The largest number of records that could appear in one bin

 = 10

B) The smallest number of records that could appear in one bin

= 1

C) The largest number of records that cab appear in one bin

= 10

d) smallest number

= 1

e) With frequency = 20. the largest number of records that could appear in one bin with equal width discretization (10 bins)

= 20

f ) with equal height discretization

= 10

6 0
3 years ago
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