Answer:
import java.util.Scanner;
public class DashLine {
public static void main(String[] args) {
// Declaring variables
int n;
/*
* Creating an Scanner class object which is used to get the inputs
* entered by the user
*/
Scanner sc = new Scanner(System.in);
// Getting the input entered by the user
System.out.print("Enter a number :");
n = sc.nextInt();
// calling the method by passing the user entered input as argument
dashedLine(n);
}
//This method will print the dashed line for number greater than zer
private static void dashedLine(int n) {
if (n > 0) {
for (int i = 1; i <= n; i++) {
System.out.print("-");
}
System.out.println();
}
}
}
Explanation:
The answer for your problem is "super computer" These types of computers can processes 1 million or more digit numbers in one second.
Answer:
void doublelt(int *number)
{
*number=*number*2;
}
Explanation:
This exercise is for you to learn and understand the PASS BY POINTER syntax. The importance of this is that if you didnt use a pointer you would have to RETURN an int from the function. in that case the code would be:
int doublelt(int number)
{
number=number*2;
return number;
}
Passing by pointer manipulates the value by going inside the memory and where it resides. Without the pointer, the function would create COPIES of the argument you pass and delete them once the function ends. And you would have to use the RETURNED value only.
