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Vikentia [17]
3 years ago
8

Int[] myArray1= new int[24]; int[] myArray2= new int[10]; float[] myArray3= new float[8]; int index1, index =0 for(int index1 =0

; index1<24; index1++){ myArray1[inex1]=index1*2; index2=index1%10; index3=index1%8; myArray2[index2] = index3 + index 2 + myArray1[index1]; myArray3[index23 = myArray1[index2] + index3;
Computers and Technology
1 answer:
anastassius [24]3 years ago
3 0

Answer:

The value of myArray2[index2] when index1 = 12 is 30

Explanation:

In the source code, the formula for myArray2[index2] is;

   myArray2[index2] = index2 + index3 + myArray1[index1],

   myArray1[index1] = index1 * 2,

   index2 = index % 10 (equal to the remainder) and

   index3  = index % 8

When index1 increases to 12 in the for-loop statement, the "myArray1[index1]" is equal to 24, index2 is equal to 2 and index3 is 4. The total sum is equal to 30 and assigned to "myArray2[index2]".

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Write an if-else statement to describe an object. Print "Balloon" if isBalloon is true and isRed is false. Print "Red balloon" i
Marat540 [252]

Answer:

if(isBalloon== true && isRed==false) //compare the value of isBalloon variable with true value and isRed variable value with false value.

   System.out.println("Balloon");//Print Balloon

else if(isBalloon== true && isRed==true) //compare the value of isBalloon variable with true value and isRed variable value with also true value.

System.out.println("Red balloon");//Print Red  Balloon

else // when no if condition match it will execute.

System.out.println("Not a balloon"); //Print Not a Balloon

Output:

Not a balloon

Explanation:

The "if-else" statement is defined above for the problem which is given on the question. The detailed explanation of the answer is described below--

  • Firstly we need to check the "true" value for the "isBalloon" variable and "false" value for "isRed" variable. This is done in "if" statement separated with and(&&) operator which gives "true" when both are the true statement.
  • Then we need to check the "true" value for the "isBalloon" variable and "isRed" variable. For this, we need to use "else if" statement which executes when "if" statement is false.
  • Then we need to print the "Not a balloon" statement if both cases are false, for this, we use "else" statement which executes when the "if" and "else if" statement are false.

6 0
4 years ago
If you have machines doing jobs, fewer staff are needed, therefore costs are
elena55 [62]
If you have machines doing jobs, fewer staff is needed, therefore the costs are LESS.

Hope I helped!
4 0
3 years ago
Read 2 more answers
What does xhtml stand for?
igomit [66]
Extensible Hypertext Markup Language.
3 0
3 years ago
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How would you print from 1 to 1000
Hitman42 [59]

Answer:

There are two ways to print 1 to 1000

  1. Using Loops.
  2. Using Recursion.

Explanation:

Using loops

for(int i=1;i<=1000;i++)

{

  cout<<i<<" ";

}

Using recursion

Remember you can implement recursion using a function only.

void print(int n)

{

  if(n==0)

  return;

  print(n-1);

  cout<<n<<" "';

}

you should pass 1000 as an argument to the function print.

5 0
3 years ago
Explain the consequences of using bits to represent data.
neonofarm [45]

Answer:

Each description of a PC needs to clarify how the PC handles data: numbers, text, pictures, sound, films, directions.

Using bits to represent data implies that the computer has to use a lot of memory since every character has a group of bits representing it.

The PC is an electronic gadget. Every one of its wires can either convey electric flow or... not convey current. Thus, similar to a light switch, it sees just two states. Incidentally, this is sufficient to make the entire thought work. Indeed, any framework that can speak to in any event two states can speak to data. Take, for instance, the Morse code that is utilized in telecommunication. Morse is a sound transmission framework that can convey a short signal (spoke to by a dab) and a long beeeeeep (spoke to by a scramble). Any letter or number can be spoken to by a mix of these two images. Snap here to see a Morse interpreter.

Explanation:

Essentially with PCs. To speak to a number, we utilize the parallel number-crunching framework, not the decimal number framework that we use in regular day to day existence. In the double framework, any number can be spoken to utilizing just two images, 0 and 1. (Morse is nearly, yet not exactly (because of the delays between letters) a paired framework. A framework firmly identified with Morse is utilized by PCs to do information pressure (more about this later).

7 0
3 years ago
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