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EastWind [94]
3 years ago
12

Helpppppppppp!!! :( math up ):

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

A 4/5 × 10 1/2 =8.4

B 2 1/2 × 16/5 =8

C 3 2/3 × 2 1/2 = 330/36 = 9.1666

D 20/3 × 9/10 =6

C IS THE GREATEST because 9.166 is greater than 8.4, 8 and 6

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8 millions + 6 thousands + 9 hundreds + 7 ones = 806. 907 A True. b.false​
suter [353]

Answer:

true

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Write an equation of a line in slope-intercept form that passes through the point (-2, 4) and has a slope of -3. (no spaces in y
mrs_skeptik [129]

Answer:

y = - 3x - 2

Step-by-step explanation:

Step 1:

y = mx + b     Slope Intercept Form

Step 2:

y = - 3x + b     Input Slope

Step 3:

4 = - 3 ( - 2 ) + b     Input x and y

Step 4:

4 = 6 + b     Multiply

Step 5:

- 2 = b       Subtract 6 on both sides

Answer:

y = - 3x - 2

Hope This Helps :)

8 0
3 years ago
HELP! Which points could be on the line that is parallel to gh and passed through point J ? Check all that apply
denis23 [38]
The first thing we are going to do in this case is find the slope of the GH line.We have then:
 m = (y2-y1) / (x2-x1)
 Substituting values:
 m = (- 2-1) / (2 - (- 4))
 m = (- 3) / (6)
 m = -1 / 2
 Then, the generic equation of the line is:
 y-yo = m (x-xo)
 Since the lines are parallel, then the slope is the same
 m = -1 / 2
 The line passes through point J, that is:
 (xo, yo) = (1, 3)
 The equation of the line will then be:
 y-3 = (- 1/2) (x-1)
 Rewriting:
 y-3 = (- 1/2) x + 1/2
 y = (- 1/2) x + 1/2 + 3
 y = (- 1/2) x + 7/2
 The points that pass through this line are:
 (-3, 5)
 5 = (- 1/2) (- 3) +7/2
 5 = 3/2 + 7/2
 5 = 10/2
 5 = 5
 (3, 2)
 2 = (- 1/2) (3) +7/2
 2 = -3 / 2 + 7/2
 2 = 4/2
 2 = 2

 (5, 1)
 1 = (- 1/2) (5) +7/2
 1 = -5 / 2 + 7/2
 1 = 2/2
 1 = 1
 Answer:
 (-3, 5)
 (3, 2)
 (5, 1)
3 0
3 years ago
Read 2 more answers
Answers? Thanks so much in advance for any help :)
LuckyWell [14K]
13. AC=6 

sorry it's just a guess i'm like 99% sure tho
8 0
3 years ago
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
3 years ago
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