10^2 + 4 * (6 + 3) - 27 ÷ (9 - 6) = 127
=100 + 4 * 9 - 27 ÷ 3
multiplication & division before addition and subtraction (order of operations rules, PEMDAS)
100 + 36 - 9= 127
136 - 9= 127
127= 127
Place a set of parentheses around (6+3) and (9-6).
Hope this helps! :)
Step-by-step explanation:
98 = 188t - 16t^2
-16t^2 + 188t = 98
-16t^2 + 188t - 98 = 0
8t^2 - 94t + 49 = 0
Use the quadratic formula with a = 8 , b = -94 , c = 49 to get the solutions
t = [(47 - root 1817) / 8]≈ 0.55
and
t = [(47 + root 1817) / 8] ≈ 11.20
Answer:
99 points
Step-by-step explanation:
Average of a data a is the sum of the data divided by the number of data.
Average = sum of data ÷ number of data
A = T/n .....1
For the average of 5 test to be 90.
The total sum of score must be;
Number of tests n = 5
Average A = 90
Substituting into equation 1
90 = T/5
T = 90×5 = 450 points
The total score must be equal to 450 point to have an average of 90 points
The sum of the first four test is;
88+84+88+91 = 351
Let x represent the first score,
351 + x = 450
x = 450 - 351
x = 99 points
The minimum score she can get in the fifth test is 99 points
