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marysya [2.9K]
3 years ago
5

1. Petra tenía 49 canicas azules y dos canicas rojas. ¿Cuántas canicas deberá quitar Petra para qu

Mathematics
2 answers:
Mazyrski [523]3 years ago
6 0

Answer:

Me no espanol

Step-by-step explanation:

LOL

-Dominant- [34]3 years ago
4 0

Answer:

Petra tendría que sacar 40 canicas azules y un roja

de esta manera habria 9 azules y una roja

pls mark brainliest

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PLEASE HELP! 15 POINTS!
Alex Ar [27]

For every x value, there should be only one y value. Or, for every input there is only one output.

A - Incorrect - there are two 2's for the x values and each of them has a different y value

B - Correct - all of the x values are different and all of the y values are different

C - Incorrect - there are two 11's for the x values and each of them has a different y value

D - Incorrect - there are two 3's for the x values and each of them has a different y value

Hope this helps! :)

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52% of what number of 109
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Answer:

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Step-by-step explanation:

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Bradley bought 14 yellow highlighters. each highlighter cost $0.94.how much did Bradley spend?
Svetradugi [14.3K]
The answer would be 13.16$

0.94x14=13.16
6 0
3 years ago
What is 23.4 x 0.4 equals
Hunter-Best [27]
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3 years ago
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The first term of an AP is -7 and the ratio of the eight term to the third term is 7:1 calculate the common difference
alukav5142 [94]

Answer:

the common difference is 6.

Step-by-step explanation:

Given;

first term of an AP, a = -7

let the common difference = d

The third term is written as;

T₃ = a + 2d

The eight term is written as;

T₈ = a + 7d

The ratio of the eight term to third term = 7:1

\frac{T_8}{T_3} = \frac{7}{1} = \frac{a+ 7d}{a + 2d} \\\\7 =  \frac{a+ 7d}{a + 2d}\\\\Recall, a = -7\\\\7 =   \frac{-7+ 7d}{-7 + 2d}\\\\7(-7 + 2d) = -7+ 7d\\\\-49 + 14d = -7 + 7d\\\\14d -7d = -7 + 49\\\\7d = 42\\\\d = \frac{42}{7} \\\\d = 6

Therefore, the common difference is 6.

4 0
3 years ago
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