Whats 9+10??????????
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Answer:
○ 3
○ y + ½ = 3(x - 2)
○ Multiply both sides of the equation by 3. The Standard Form of the equation is 12x - 2y = 24.
○ 5x - 3y = 15
○ y = ½x + 5⁄2
Step-by-step explanation:
Find the <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>]:
-y₁ + y₂\-x₁ + x₂ = m → (-1, 1) and (-2, -2)
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According to the Point-Slope Formula, <em>y - y₁ = m(x - x₁)</em>, all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting this coordinate into the formula with their CORRECT SIGNS:
(2, -½) → y + ½ = 3(x - 2)
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We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it:
-3[4x - ⅔y = 8] → -12x + 2y = -24
** They should have multiplied by -3 instead of 3 because that negative is hooked up to everything in the fraction, but since the exercise gave you 12x - 2y = 24, go with 12x - 2y = 24.
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If you would take a look at this graph real closely, you will see that this graph intersects the y-axis and x-axis at ENDPOINTS, so to find the x-intercept, you simply plug in <em>zero</em> for <em>y</em>: 5x = 15, and you will know right away that <em>x</em><em> </em>is set to equal 3, which is what you see in the graph, (3, 0). Now, to find the y-intercept, you simply plug in <em>zero</em><em> </em>for <em>x</em>: -3y = 15, and you will know right away that <em>y</em><em> </em>is set to equal -5, which is what you see on the graph as well, (0, -5). With that being said, you have your answer.
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y - 3 = ½(x - 1)
y - 3 = ½x - ½
+ 3 + 3
_____________
y = ½x + 2½
* 2½ = 5⁄2
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Answer:
The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.
If the test is done anyway, the null hypothesis failed to be rejected.
The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.
Step-by-step explanation:
The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.
If the test of hypothesis is done as if the conditiones were met, we know that the claim is that the percentage is lower in this district.
Then, the null and alternative hypothesis are:
The significance level is 0.05.
The sample has a size n=80.
The sample proportion is p=0.1.
The standard error of the proportion is:
Then, we can calculate the z-statistic as:
This test is a left-tailed test, so the P-value for this test is calculated as:
As the P-value (0.057) is greater than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the percentage is lower in this district.