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3 years ago

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Select all of the relations that are functions. {(a, 1), (b, 1), (c, 1)} {(a, a), (a, b), (a, c)} {(1, a), (2, a), (3, a)} {(a,

a), (b, b), (c, c)}

1 answer:

netineya [11]3 years ago

5 0

Answer:

{(a, 1), (b, 1), (c, 1)}, {(1, a), (2, a), (3, a)}, and {(a, a), (b, b), (c, c)}

**All functions are relations, but not ll relations are functions**

In a function, the x values CAN NOT repeat, only y-values can.

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The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th

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Answer:

CLASS FREQUENCIES RELATIVE FREQUENCIES

A 60 0.5

B 12 0.1

C 48 0.4

TOTAL 120 1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

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Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

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therefore;

CLASS FREQUENCIES RELATIVE FREQUENCIES

A 60 0.5

B 12 0.1

C 48 0.4

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3 years ago

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grigory [225]

Answer:

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Step-by-step explanation:

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3 years ago

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4 years ago

Suppose that the quarterly sales levels among health care information systems companies are approximately normally distributed w

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Answer:

The cutoff sales level is 10.7436 millions of dollars

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 12, \sigma = 1.2$

15th percentile:

X when Z has a pvalue of 0.15. So X when Z = -1.047.

$Z = \frac{X - \mu}{\sigma}$

$-1.047 = \frac{X - 12}{1.2}$

$X - 12 = -1.047*1.2$

$X = 10.7436$

The cutoff sales level is 10.7436 millions of dollars

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3 years ago