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ddd [48]
3 years ago
11

Select all of the relations that are functions. {(a, 1), (b, 1), (c, 1)} {(a, a), (a, b), (a, c)} {(1, a), (2, a), (3, a)} {(a,

a), (b, b), (c, c)}
Mathematics
1 answer:
netineya [11]3 years ago
5 0

Answer:

{(a, 1), (b, 1), (c, 1)}, {(1, a), (2, a), (3, a)}, and {(a, a), (b, b), (c, c)}

**All functions are relations, but not ll relations are functions**

In a function, the x values CAN NOT repeat, only y-values can.

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<span>h = –16t 2 + 64t + 8
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0 = -16t^2 + 64t +8

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Step-by-step explanation:

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\large{\green}\fcolorbox{purple}{pink}{\bf{\underline{\red{\color{red}Answer}}}}

6x + 20

Step-by-step explanation:

  • <u>To</u><u> </u><u>find</u><u> </u><u>:</u><u>-</u>

Perimeter of rectangle

  • <u>Given</u><u> </u><u>:</u><u>-</u>

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<em>We</em><em> </em><em>know</em><em> </em><em>that</em>

<em>\mathfrak {perimeter \: of \: rectangle =2(length + breadth) }</em>

<em>Now</em><em> </em><em>we</em><em> </em><em>will</em><em> </em><em>substitute</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>length</em><em> </em><em>and</em><em> </em><em>breadth</em>

<em>\sf  \longmapsto perimeter = 2 \{(2x + 7) + (x + 3) \} \\  \\  \\  \sf \longmapsto perimeter = 2 \{3x + 10 \} \\  \\  \\  \sf  \longmapsto perimeter = 6x + 20</em>

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