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kenny6666 [7]
3 years ago
8

Which statement about the number of earthquakes the

Mathematics
1 answer:
Lelechka [254]3 years ago
7 0

Answer:

<u>State A had approximately 1,533 more earthquakes than  State B.</u>

Step-by-step explanation:

<u>Earthquake:</u> The term "earthquake" is determined as the surface shaking of the uppermost layer of the earth that often results from the absurd release of specific energy in the "earth's lithosphere" that tends to create "seismic waves". However, the intensity of the earthquake varies time to time and the weak tremor is rarely being noticed as compared to the higher ones.

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A person is standing on a cliff that is 200ft above a body of water. The person looks down at an angle of depression of 42o at a
velikii [3]

Answer:

524.5 feet

Step-by-step explanation:

Given: Height of cliff= 200 ft

           Angle of depression at sail boat is 42°

           Angle of depression at yacht is 15°

Lets assume distance sailboat from the bottom of cliff is "d_1"

And assume distance yacht from the bottom of cliff is "d_2"

Now using tangent rule to solve it.

we know, tan\theta = \frac{opposite}{adjacent}

Distance sailboat from the bottom of cliff; tan 42= \frac{200}{d_1}

Using trignometry table to know the value of tan 42°

⇒0.90= \frac{200}{d_1}

cross multiplying both side.

⇒ d_1= \frac{200}{0.90} = 222.22 \approx 222

∴ Distance sailboat from the bottom of cliff (d_1)= 222 feet

Distance yatch from the bottom of cliff; tan 15= \frac{200}{d_2}

Using trignometry table to know the value of tan 15°

⇒0.2679= \frac{200}{d_2}

cross multiplying both side.

⇒ d_2= \frac{200}{0.2679} = 746.54 \approx 746.5

∴Distance yacht from the bottom of cliff (d_2)= 746.5 feet.

Next, finding the distance between sailboat and yacht.

Distance between sailboat and yacht = d_2-d_1

⇒ Distance between sailboat and yacht= 746.5-222= 524.5\ ft

∴ Distance between sailboat and yacht is 524.5 feet.

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