Answer:
12n+9=93
solve for n
12n=93-9
n=84/12
n=7
therefore, Mr. copper bought 7 tickets.
Answer:
The graph of the parabola is represented by the quadratic function
y = a( x - p )2 + q which has an axis of symmetry represented by the equation of the vertical line x = p.
Step-by-step explanation:
Answer:
0.00069104 approximately.
Step-by-step explanation:
You must first calculate the probability of not taking a ball with the letter B.
It would be the sum of the probabilities of taking I, N, G and O.
The probability of getting the letter I would be 15/75, that is 1/5. The same would be for the letter N, G and O. Since the 4 probabilities are equal.
Therefore it would remain (1/5) * 4 = 4/5.
Then the probability of not drawing a letter B would be 4/5.
However, in the case that it does not go out for 26 balls and that the ball that was taken out is not taken into account. It would be the multiplication of all events, that is:
(60/75) * (59/74) * (58/73) * (57/72) * ... * (35/50)
The result would be 0.00069104 approximately.
Answer: see explanation
Step-by-step explanation:
so you have a plane at constant altitudeof 6km (6000m) flying at 800 km/h (222.222 m/s) (see the image)
the plane is moving with constant speed therefore x(t) = 222.222*t => no forces are interacting horizontally with the plane therefore acceleration is 0, then v is constant and x(t) is a linear function which coefficient is v.
now we have a triangle with an angle theta, one side is x(t), and the other is 6000m. we can get theta by tan(theta) = 6000/(222.222*t). 24 minutes are 1440 seconds so if we replace such value, we get the theta angle by solving for theta => theta = arctan(6000/(222.222*1440)) = 0.019 radians or 1.074 degrees. Now if you want to know the exchange rate of theta we have to differentiate the expression with respect to t:

then replace t with 1440 and you will get that theta is changing by -0.000013 (1.3E-5) radians or -7.458E-4 degrees every second which has a lot of sense since the plane is getting out of your line of sight due to the earth's curvature