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Sergio has 79 paintings in his art collection. He and other local painting collectors agreed to donate some paintings to the loc
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6 phone numbers are possible for one area code if the first four numbers are 202-1
<u>Solution:</u>
Given that, the first four numbers are 202-1, in that order, and the last three numbers are 1-7-8 in any order
We have to find how many phone numbers are possible for one area code.
The number of way “n” objects can be arranged is given as n!
Then, we have three places which changes, so we can change these 3 places in 3! ways
Hence 3! is found as follows:
So, we have 6 phone numbers possible for one area code.
Answer: x < 2
Explanation: To solve for <em>x</em> in this inequality, our goal is the same as it would be if this were an equation, to get <em>x</em> by itself on one side.
Since 3 is being subtracted from <em>x</em>, we add 3
to both sides of the inequality to get <em>x < 2</em>.
Before we graph, write your answer in set notation.
We can write this as {x: x < 2}.
It's important to understand what this means.
This means that any number less than 2 is a solution to this inequality.
I have graphed the inequality for you below.
Start with an open dot on +2.
We use an open dot because +2 is not included as a solution.
Then draw an arrow going to the left.
