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3 years ago

The total bill for dinner it was $79 how much money should the group leave if they want to leave a 15% tip? PLEASE HELP!!!!

Mathematics

2 answers:

inessss [21]3 years ago

7 0

i’m pretty sure it’d be $11.85 for the tip

Fynjy0 [20]3 years ago

6 0

15$ so yeah help me please I am so super stuck

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Three vertices of parallelogram ABCD are A(−2, −2), B(2, 1), and C(0, 7). What are the coordinates of vertex D?

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3 years ago

Prove the polynomial identity (a-1)^3 + (a-1)^2 = a(a-1)^2

Sav [38]

Answer:

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Step-by-step explanation:

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3 years ago

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the ratio of the lenghts of corresponding parts in two smillar solids is 4.1 what is the ratio of their surface areas?

victus00 [196]

Answer:

16:1

Step-by-step explanation:

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(4:1)²

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3 years ago

A campus deli serves 101 customers over its busy lunch period from 11:30 am to 1:30 pm. A quick count of the number of customers

iogann1982 [59]

Answer:

21.38 minutes

Step-by-step explanation:

the total number served = 101

teh number of hours that is spent in serving from 11.30 to 1.30 = 2 hours

Lq = average number of those that are in line = 18 customers

from here we are to find the flow rate

= $\frac{total served}{service hour}$

= 101/2 = 50.5

the average time in waiting =

Lq/flow rate

= 18/50.5

= 0.3564 hours

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4 0

3 years ago

A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula

Ilia_Sergeevich [38]

Answer: A. $A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}$

B. A'(5) = 1.76 cm/s

Step-by-step explanation: Rate of change measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

$A=\pi.r^{2}$

So to find the rate of the area:

$\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}$

$\frac{dA}{dr} =2.\pi.r$

Using $r(t)=3-\frac{363}{(t+11)^{2}}$

$\frac{dr}{dt}=\frac{726}{(t+11)^{3}}$

Then

$\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]$

$\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}$

Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

The rate at which the area is increasing is given by expression $A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$ .

B. At t = 5, rate is:

$A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}$

$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

$A'(5)=\frac{2408693760\pi}{4294967296}$

$A'(5)=1.76268$

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0

3 years ago