A
see attached for explanation
I hope it helps
Answer:
a³ + b³
Step-by-step explanation:
Given
(a + b)(a² - ab + b²)
Each term in the second factor is multiplied by each term in the first factor, that is
a(a² - ab + b²) + b(a² - ab + b²) ← distribute both parenthesis
= a³ - a²b + ab² + a²b - ab² + b³ ← collect like terms
= a³ + b³
The solution is -5/4= -1 1/4
A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.
Answer:
-4 and 3
Step-by-step explanation: