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Mumz [18]
3 years ago
8

Please answer this question now

Mathematics
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

e =7.1

Step-by-step explanation:

Hypotenuse = 10\\Opposite =e\\Adjacent =7\\\\Using\:Pythagoras\:Theorem\\Hypotenuse^2=Opposite^2+Adjacent^2\\10^2 =e^2 + 7^2\\100 =e^2+49\\100-49=e^2\\\\51 =e^2\\\sqrt{51} =\sqrt{e^2}\\ e = 7.141\\\\e = 7.1

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A line has an x-intercept of 4 and a y-intercept of -2. What is the equation of the line?
Evgesh-ka [11]

Answer:

y=x/2-2

Step-by-step explanation:

it's actually 1/2 times x is how your supposed to write it (like a fraction)

7 0
3 years ago
Shenise is a star player for her women's basketball team. She has injured her ankle, and it is doubtful that she will be able to
Sladkaya [172]

Answer:

<u>The correct answer is that it's expected the team will score 72 points.</u>

Step-by-step explanation:

1. This is the information given in the question:

When Shenise can play the team scores 91 points

Without Shenise the team just scores 60 points

Therefore, when Shenise is at her best, her 100%, she scores 31 points by herself. When she's not in conditions, she can't play.

2. For finding out how many points Shenise can score if she plays, we use this formula:

If Shenise is at her 100%, she scores 31 points, how many points can she score if she's at 40% chance of playing?

Points upcoming game = 31 * 40 / 100

Points upcoming game = 1,240 / 100

Points upcoming game = 12.40 = 12 (rounding to the nearest whole number)

3. If Shenise plays, she can score 12 points. Now, we can calculate how many points her team will score.

Points the team scores when Shenise doesn't play = 60

Points the team will score if Shenise plays = 60 + 12 = 72

<u>The team will probably score 72 points with a 40% chance that Shenise will play the upcoming game</u>

4 0
3 years ago
Which equation represents the graphed line? linear graph y=5
schepotkina [342]

y=-2x+5

Hope that helps :D

4 0
3 years ago
Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
3 years ago
There are two similar packages. The ratio of the volumes is 8:125. Determine the dimensions of the bigger package. The dimension
GREYUIT [131]

Step-by-step explanation:

since packages are similarsimilar packages. The ratio of the volumes is 8:125. Determine the dimensions of the bigger package. The dimensions of the smaller package are... Height= 45cm, Length= 80cm, and Width= 25cm.

Length of bigger package = <em><u>8</u></em><em><u>0</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>0</u></em><em><u>c</u></em><em><u>m</u></em>

Width of bigger package =<em><u>2</u></em><em><u>5</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>3</u></em><em><u>9</u></em><em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u>2</u></em><em><u>5</u></em><em><u>c</u></em><em><u>m</u></em>

Height of bigger package =<em><u>4</u></em><em><u>5</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>7</u></em><em><u>0</u></em><em><u>3</u></em><em><u>.</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>cm</u></em>

4 0
2 years ago
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