Answer:
B. XV and XY
Step-by-step explanation:
you can eliminate the top two options because those aren't rays. XV and XY are the only ones that end in X
Answer:
Step-by-step explanation:
We can solve this in either of two ways. I'll do both.
<u>Mathematically</u>
3x + 2y = 8
5x + 2y = 12
Rewrite either equation to isolate y. I'll use
3x + 2y = 8
2y = 8 - 3x
y = (8-3x)/2
Now use this value of y in the other equation:
5x + 2y = 12
5x + 2((8-3x)/2) = 12
5x + (8 - 3x) = 12
2x = 4
x = 2
Use x=2 to find y:
y = (8-3x)/2
y = (8-3*(2))/2
y = (8-6)/2
y = 1
The point is (2,1)
<u>Graphically</u>
Graph the two equations and find the point they intersect. See attachment.
We obtain the same answer: (2,1)
<u>We are provided that</u> –
<u>Applying identity</u> –



Answer:yes
Step-by-step explanation:
<h3>
Answer: Choice B</h3>
Consider that choice B is the same as saying 2x^2+1x^0.
The exponents 2 and 0 are both even, which is sufficient to say that the entire polynomial function itself is also even.
Something like choice A expands out and simplifies to x^2-2x+2, and that's equivalent to saying x^2+2x^1+2x^0. The presence of the x^1 term, with its odd exponent, is what makes choice A not even (it's not odd either).
Similarly, choices C and D also have exponents of 1, so they aren't even either.