Basing the results on Probability is calculation. The correct option among all the options that are given in the question is the third option or option "c". Probability is basically calculating the chance of an event happening based on an experiment that is performed. I hope the answer comes to your help.
It is 10 times as much as .008
Do you see the pattern?
Answer: 4![\sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%7D)
Step-by-step explanation:
Answer:
x= 81°, z= 99°, y°=68°
Step-by-step explanation:
considering the part of the triangle where 36° , 63° and x° is located as ΔABC.
to find the measure of x we use angle sum property.
We know that the sum of the angles of a triangle is always 180°. Therefore, if we know the two angles of a triangle, and we need to find its third angle, we use the angle sum property. We add the two known angles and subtract their sum from 180° to get the measure of the third angle.
so,
∠A + ∠B +∠C = 180°
36° + 63° + x° = 180°
99° + x° = 180°
x° = 180 - 99
x° = 81°
When two lines intersect each other at a single point, linear pairs of angles are formed. If the angles so formed are adjacent to each other after the intersection of the two lines, the angles are said to be linear. If two angles form a linear pair, the angles are supplementary, whose measures add up to 180°.
x° + z° = 180°
81° + z = 180°
z= 180 - 81
z= 99°
considering the next part of the triangle where 13° , z° and y° is located as ΔACD
to find the measure of y we use angle sum property.
∠A + ∠C + ∠D = 180°
13° + z° + y° = 180°
13°+99°+y°= 180°
112°+ y° = 180°
y°= 180- 112
y° = 68°
Answer:
Mean = 35
Variance = 291.7
Step-by-step explanation:
Data provided in the question:
X : 1, 2, 3, 4, 5, 6
All the data are independent
Thus,
The mean for this case will be given as:
Mean, E[X] = 
or
E[X] = 
or
E[X] = 3.5
For 10 days, Mean = 3.5 × 10 = 35
And,
variance = E[X²] - ( E[X] )²
Now, for this case of independent value,
E[X²] = 
or
E[X²] = 
or
E[X²] = 
or
E[X²] = 15.167
Therefore,
variance = E[X²] - ( E[X] )²
or
variance = 15.167 - 3.5²
or
Variance = 2.917
For 10 days = Variance × Days²
= 2.917 × 10²
= 291.7