Answer:
-1
Step-by-step explanation:
i think thats corrext
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
1/3 + 7x = 1/3 + 7(5 )=
1/3+35
=1/3 + 105/3 =
106/3=
35 1/3
Answer:
The area of tarpaulin is 1315.63 ft^2.
Step-by-step explanation:
height, h = 20 feet
circumference, C = 102 feet
Let the radius is r.
Circumference, C = 2 x 3.14 x r = 102
r = 16.24 feet
Let the slant height is L.
The curved surface area is
S = 3.14 x r x L
S = 3.14 x 16.24 x 25.8 = 1315.63 ft^2
