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GrogVix [38]
3 years ago
11

!!PLEASE ANSWER!!

Mathematics
2 answers:
lesya [120]3 years ago
5 0
I think its b because a coefficient is a number that is placed in front of a variable and the 4 is just a constant
tekilochka [14]3 years ago
5 0

Answer:

The "2" in the second term is a coefficient.

Step-by-step explanation:

3x^2-11(2y+1)+4

In the given expression ,

3 in the first term is a the coefficient of x^2

11 is the factor of second term

4 is the constant in third term

2 is the coefficient of y

So, The "2" in the second term is a coefficient.

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(5,-2 is on which quardrant
blondinia [14]

Answer:

Quadrant IV, or the fourth quadrant.

Step-by-step explanation:

Plot your points, first plotting 5, then plotting -2.

4 0
3 years ago
line passes through the point (0, –1) and has a positive slope. Which of these points could that line pass through? Check all th
sammy [17]

Answer:

Points passing though are (12, 3),(–2, –5) and (1, 15)

Step-by-step explanation:

For a line passing through (x₁,y₁) and (x₂,y₂) slope is given by \frac{y_2-y_1}{x_2-x_1}.

Here we have one point (0, –1), we need to check slope of all the points given.

(12, 3)

          m=\frac{3-(-1))}{12-0}=\frac{1}{4}>0

(–2, –5)

          m=\frac{-5-(-1))}{-2-0}=\frac{-4}{-2}=2>0

(–3, 1)

         m=\frac{1-(-1))}{-3-0}=\frac{2}{-3}=-\frac{2}{3}

(1, 15)

        m=\frac{15-(-1))}{1-0}=\frac{16}{1}=16>0

(5, –2)

        m=\frac{-2-(-1))}{5-0}=\frac{-1}{5}=-\frac{1}{5}

Points with positive slope are (12, 3),(–2, –5) and (1, 15)

8 0
4 years ago
Read 2 more answers
Solve each system by graphing y=-x+5 and y=2x-4
makkiz [27]
In order to graph y=-x+5, make a table and plug in values of x to find y. to find your points, use x,y. 
x: 1  y: 4
x: 2  y: 3
x:3  y: 2
x: 2  y:1
these are the first four points for the first equation. to plug in, use ramdom numbers for x, such as 1, 2, and 3. y= -(1) +5
7 0
3 years ago
Find the slope 9,4 and 0,5
son4ous [18]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ 9}} &,&{{ 4}}~) 
%  (c,d)
&&(~{{ 0}} &,&{{ 5}}~)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{5-4}{0-9}\implies \cfrac{1}{-9}\implies -\cfrac{1}{9}
7 0
3 years ago
Look at the given triangles
emmainna [20.7K]
I think the answer is C but i could be wrong
3 0
3 years ago
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