Answer:
8
Step-by-step explanation:
<h3>
Answer: 9</h3>
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Work Shown:
a = unknown = leg #1
b = 12 = leg #2
c = 15 = hypotenuse
Plug those values into the pythagorean theorem and solve for 'a'
a^2 + b^2 = c^2
a^2 + (12)^2 = (15)^2 .... substitution
a^2 + 144 = 225
a^2 = 225 - 144 ... subtracting 144 from both sides
a^2 = 81
a = sqrt(81) .... applying square root to both sides
a = 9
Put a point H on (9, 2). Sketch a triangle out of the three points. Distance between (-2, 2) and (9, 2) is going to be 11. Distance between (9, 2) and (9, 5) is going to be 3. These correspond to the a and b of the Pythagorean Theorem
c^2=a^2+b^2
c=√11^2+3^2=√130
<span>Square root of 130 is 11.4</span>
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Answer:
Step-by-step explanation:
2 x 2 = 1 the interception of it
