d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
Answer:
∠1 = 72°
Step-by-step explanation:
Complementary angles sum to 90°, thus
∠1 + ∠2 = 90, substitute ∠1 = 4∠2 , thus
4∠2 + ∠2 = 90
5∠2 = 90 ( divide both sides by 5 )
∠2 = 18°
Hence ∠1 = 90 - 18 = 72°
Answer:
1.5 feet
Step-by-step explanation:
there are three feet in a yard, so 8*3= 24, and 24/16=1.5 feet of ribbon used for each bow
Answer:
Step-by-step explanation:
Given: m∠1 = 62° and lines t and l intersect
Prove: m∠4 = 62°
Proof:
Statement Reason
m∠1 = 62° Given
m∠1 , m∠2 are supplementary t is a straight line hence linear pair.
m∠4 , m∠2 are supplementary r is a straight line hence linear pair.
Angle 2=180-62 = 118 Definition of supplementary angles
Angle 4 = 180-118 =62 -do-
Angle 1 = Angle 4 Equality property
Hence proved
C)
10hrs will get around 105 salaries
90hrs get 840+105=945
95 hours get 945+(105/2)=997.5
100 hours get 945+105=1050
