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scZoUnD [109]
4 years ago
12

Find the elapsed time.

Mathematics
1 answer:
coldgirl [10]4 years ago
4 0

Answer:

24) 2:15

25) 4:15

26) 3:45

27) 0:20

28) 18:00

29) 5:47

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Help! im stuck on part B!
luda_lava [24]

Answer:

sjlsalllaalldjjsjjjaajldljD

Step-by-step explanation:SDK

s

d

d

d

4 0
3 years ago
HELPPP KE PJEASE. ASAPPPP ITS FOR A QUIZZZ
san4es73 [151]
=(1/2) * 2 * 3.2 + (1/2) *2 * 3.2 + (1/2) * 2 * 4 + (1/2) * 2 * 4
= 2 * 3.2 + 2 * 4
= 2 * (3.2 + 4)
= 2 * 7.2
= 14.4 sq feet
2 * 14.4 = 28.8 sq feet
8 0
3 years ago
What is (x+6)(x+4)(x-3) expand and simplify
mestny [16]

Answer:

x³ + 7x² - 6x - 72

Step-by-step explanation:

Given

(x + 6)(x + 4)(x - 3) ← expand the second and third factor, that is

(x + 4)(x - 3)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x - 3) + 4(x - 3) ← distribute both parenthesis

= x² - 3x + 4x - 12 ← collect like terms

= x² + x - 12

Now multiply this by (x + 6) in the same way

(x + 6)(x² + x - 12)

= x(x² + x - 12) + 6(x² + x - 12) ← distribute both parenthesis

= x³ + x² - 12x + 6x² + 6x - 72 ← collect like terms

= x³ + 7x² - 6x - 72

7 0
3 years ago
Someone please help! I'm confused with c and d.
Karo-lina-s [1.5K]

It would be 3 times the sum of x and seven plus 10. This is because first you would would add 7+x (7x) and multiply it by 3. And then add on 10.

5 0
4 years ago
Read 2 more answers
This is Matrix for pre calc
gavmur [86]

The given system of equations in augmented matrix form is

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]

If you need to solve this, first get the matrix in RREF:

  • Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]

  • Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]

  • Add 164(row 3) to -91(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]

  • Multiply row 4 by 1/13080:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]

  • Add -153(row 4) to row 3:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]

  • Multiply row 3 by -1/91:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add 6(row 3) and -8(row 4) to row 2:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 2 by 1/5:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 1 by 1/3:

\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

So the solution to this system is (w,x,y,z)=(1,-2,4,-3).

6 0
4 years ago
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