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azamat
3 years ago
15

(3m^0)^3 A. 27cm3 B. 27

Mathematics
1 answer:
abruzzese [7]3 years ago
8 0
B! 27 please mark brainliest
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Tim and Jane work for a company that sells boxes of breakfast cereal ....:
viva [34]

Answer:

yes

Step-by-step explanation:

6 0
3 years ago
Determine the ordered pair that satisfies the equation, -5x + 3y = 7.
sammy [17]

Answer:

C) (7 , 14)

Step-by-step explanation:

Substitute each ordered pair into the equation

-5x + 3y = 7.

A) (2 , -1)

-5(2) +3(1) = -10 +3 = -7  this does not equal 7  so not true

B) (-5 , 3)

-5(-5) +3(3) = 25 +9 = 34  this does not equal 7 so not true

C) (7 , 14)

-5(7) + 3(14) = -35 + 42 = 7  this equals 7 so true

D) (-2 ,−135)

-5(-2) + 3(-135) =10+405 =415  this does not equal 7 so not true

3 0
3 years ago
A power plant has 4 tons of coal. A ton of coal produces 2460 kilowatt hours of electricity. Is this enough to power 9 light bul
xz_007 [3.2K]

Answer: Yes

Step-by-step explanation:

 We will assume that each bulb is of 100 kW (kilowatt).

 We will calculate how much energy in kilowatt-hours the light bulb will use per year in kilowatts, by the number of hours in a year.

We have,  100 kW = 0.1 kW so the energy consumed in one year is,

0.1 \times 8760=876.0\text {kWh} Since there are 8760 hours in one year. It is given that there are 9 bulbs so we need to have, 876 \times 9 = 7884 \text {kWh}

It is given that 1 ton of coal produces 2460 kWh, so 4 tons of coal will produce, 4\times 2460= 9840 \text {kWh}

We can observe that 4 tons of coal is producing 9840 kWh which is mroe than 7884 kWh. So, yes, 4 tons of coal can produce enough power to light 9 bulbs for a year

6 0
3 years ago
Roy uses 1/4 of batter for each muffin. Make a list to show the amounts of batter he will use depending on the number of muffins
Allisa [31]
1/4 1. Rule: +1/4
1/2 2
3/4 3
1 4
1 1/4 5
1 1/2 6
1 3/4 7
2 8
6 0
3 years ago
Rationalize the denominator:<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%5Csqrt%7B3%7D%20%20-%20%20%20%5Csqrt%7
Vilka [71]

Answer:

________________________________

step\:1

\frac{1}{ \sqrt{3} -  \sqrt{2}  }

write the equation

________________________________

step\:2

\frac{1 \times ( \sqrt{3} +  \sqrt{2})  }{ (\sqrt{3} -  \sqrt{2} ) \times  (\sqrt{3}  +  \sqrt{2})  }

multiply both numerator and denominator by √3+√2

________________________________

step\:3

\frac{ \sqrt{3} +  \sqrt{2}  }{ ( 3 ) - ( 2 ) }

after multiplying numerator with √3+√2 we get→√3+√2

after multiplying denominator we get 3-2

________________________________

step\:4

\frac{ \sqrt{3}  +  \sqrt{2} }{1}

after subtracting 3 with 2 we get →1

________________________________

hence denominater is rationalized✓

hope it helped you:)

3 0
3 years ago
Read 2 more answers
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