Answer:
yes
Step-by-step explanation:
Answer:
C) (7 , 14)
Step-by-step explanation:
Substitute each ordered pair into the equation
-5x + 3y = 7.
A) (2 , -1)
-5(2) +3(1) = -10 +3 = -7 this does not equal 7 so not true
B) (-5 , 3)
-5(-5) +3(3) = 25 +9 = 34 this does not equal 7 so not true
C) (7 , 14)
-5(7) + 3(14) = -35 + 42 = 7 this equals 7 so true
D) (-2 ,−135)
-5(-2) + 3(-135) =10+405 =415 this does not equal 7 so not true
Answer: Yes
Step-by-step explanation:
We will assume that each bulb is of 100 kW (kilowatt).
We will calculate how much energy in kilowatt-hours the light bulb will use per year in kilowatts, by the number of hours in a year.
We have, 100 kW = 0.1 kW so the energy consumed in one year is,
0.1 \times 8760=876.0\text {kWh} Since there are 8760 hours in one year. It is given that there are 9 bulbs so we need to have, 876 \times 9 = 7884 \text {kWh}
It is given that 1 ton of coal produces 2460 kWh, so 4 tons of coal will produce, 4\times 2460= 9840 \text {kWh}
We can observe that 4 tons of coal is producing 9840 kWh which is mroe than 7884 kWh. So, yes, 4 tons of coal can produce enough power to light 9 bulbs for a year
1/4 1. Rule: +1/4
1/2 2
3/4 3
1 4
1 1/4 5
1 1/2 6
1 3/4 7
2 8
Answer:
________________________________
write the equation
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multiply both numerator and denominator by √3+√2
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after multiplying numerator with √3+√2 we get→√3+√2
after multiplying denominator we get 3-2
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after subtracting 3 with 2 we get →1
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hence denominater is rationalized✓
hope it helped you:)
