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3 years ago

13

At a local department store sweaters typically cost $44. However due to a special the sweaters are reduced to $22. What percent

of the original price has the sweater been reduced to

1 answer:

kvasek [131]3 years ago

8 0

Answer:

50% reduction in price

Step-by-step explanation:

can be determined by 44- (44× X) solve for x and you get x as .5

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|20x|=2|2x+8|<br> please show all steps <br> and both answers

lukranit [14]

Step-by-step explanation:

20x = 4x +16

16x = 16

x=1

multiply the 2 into the absolute value bars. check if there are negatives. if there aren't, bars can be removed. solve as normal

7 0

3 years ago

Answer the question and get Brainly, A sail for a boat is in the shape of a right Tiangle. The longest side is 20 ft. long. One

lana66690 [7]

Answer:

<h3>The answer is D.</h3>

Step-by-step explanation:

Explanation:

The rule of a triangle is that it the other two sides could not be longer than longest side of the triangle. If the two sides added up together is greater than the longest side, the triangle would no longer be connected. Since 8 + 12 ft still works for the longest side of the triangle, it will be considered the length of the third side.

3 0

3 years ago

Read 2 more answers

67.5 into a fraction

andrey2020 [161]

Answer:

67 1/2

Step-by-step explanation:

67 5/10

67 1/2

3 0

3 years ago

Read 2 more answers

Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of <em>f</em> :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of <em>g</em> :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So <em>f</em> has a minimum of -7 and a maximum of 299.

4 0

3 years ago

Solve for b.<br> - 32 + 106 = -22

Eddi Din [679]

Answer:

-30+10b=-22

32-22=10b

10b=10

-32+10=-22

hope it helps

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3 years ago