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Arte-miy333 [17]
3 years ago
6

If a system consists only of a linear function and an exponential graph, what is the maximum number of solutions possible of the

system?
Mathematics
2 answers:
Advocard [28]3 years ago
7 0

Answer:

One solution

Step-by-step explanation:

There will be a single solution in the graph. The solution is as a result of the intersection of the two linear systems of linear functions. The intersection gives the solution of the equations. In this case, it is only one solution.

Kaylis [27]3 years ago
3 0
A linear function can only have one solution no matter what type of graph it's on. So, the answer is one solution.
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I live for walks at a rate of 4 mph she lives 2 miles from the news station how long will it take her to walk home from the news
Tresset [83]

um half hour? because at 4mph youll get 4 miles in an hour so 2 miles, is half the rate which makes it half hour

3 0
3 years ago
Claire is cycling at a speed of 12 miles per hour. Han is cycling at a speed of 8 miles per hour. If they start at the same posi
larisa [96]

Answer:

45 minutes is 3/4 of an hour, so find 3/4 of 12.  

Divide 12 by 4 to get 1/4 of 12. That is 3.  

3/4 is 3 of those, so multiply it by 3 to get 9.

So, she will have biked 9 miles.  

8 0
3 years ago
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Tom and Bob have a total of 49 toys if Bob has 5 more toys than Tom, how many toys does each one have
pickupchik [31]
49 + 5 = 54

So the answer is 54
5 0
3 years ago
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In the set of scores: 14, 17, 10, 22, 19, 24, 8, 12, and 19, the Q2 is?
NNADVOKAT [17]

Answer:

17

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8 0
2 years ago
P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
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