Answer:
445788
Step-by-step explanation:
OMG too difficult man!!
Thanks to my calculator to solve this hard question
For finding the perimeter of abc (triangle), we MUST need the two others coordinates of b and c
let b(1, 2) and c (2, -4)
we need to calculate the distances ab, ac, and bc
vector (ab)=(1-(-2), 2-9)=(3, -7), so its length is ab=sqrt(3²+ (-7)²)=7.61
realising the same method, we find bc=6.08, ac=13.60
so the perimeter of abc is P= ab+bc+ca=13.60+6.08+7.61=27.29
Answer:
y=3/5x-1
Step-by-step explanation:
The formula you need to find this would be
(y-y1)=m(x-x1)
The y1 is your y point.
The x1 is your x point.
m is your slope.
Start by plugging in your numbers that they provide you.
(y-8)=3/5(x-15)
Now you need to distribute the slope to the terms inside the parenthesis next to it.
3/5(x)=3/5x
3/5(-15)= -9 Now you put those back into the equation.
(y-8)=3/5x-9
At this point you can get rid of the parenthesis around the y-8 since it is basically saying to take the term times 1.
To get y alone we not need to add 8 to both sides.
y-8=3/5x-9
+8 +8
y=3/5x-1
Can I see a pic? But 3/2 is like three divided by two so the answer would be 1.5
