<u>Hint </u><u>:</u><u>-</u>
- Break the given sequence into two parts .
- Notice the terms at gap of one term beginning from the first term .They are like
. Next term is obtained by multiplying half to the previous term . - Notice the terms beginning from 2nd term ,
. Next term is obtained by adding 3 to the previous term .
<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>
We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,
.
We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,
Notice the term
will be too small , so we can neglect it and take its approximation as 0 .

Now the second sequence is in Arithmetic Progression , with common difference = 3 .
![\implies S_2=\dfrac{n}{2}[2a + (n-1)d]](https://tex.z-dn.net/?f=%5Cimplies%20S_2%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D%20)
Substitute ,
![\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}](https://tex.z-dn.net/?f=%5Cimplies%20S_2%3D%5Cdfrac%7B25%7D%7B2%7D%5B2%284%29%20%2B%20%2825-1%293%5D%20%3D%5Cboxed%7B%20908%7D%20)
Hence sum = 908 + 1 = 909
Answer:
<u>A. Quadratic, degree 2</u>
Step-by-step explanation:
The degree is found by simply finding the term with the power of, that is the highest. Which would be 2x^2. It is raised to the 2nd power, so the degree is 2.
i dont think you have a whole question down and we need examples of the triangles so please shw examples
Answer:
he will be 17 in
Step-by-step explanation:
<span>To solve this, use the point - slope form formula
</span>Point D (-4, 2) and Point E (-1, 5)
<span>y - y1 = [(y2 - y1)/(x2 - x1)](x - x1)
y - 2 = [(5 - 2/-1 -(-4))](x + 4)
y - 2 = x + 4
y = x + 6
To answer this, input the values of points D or E into the equation and make sure that they answer the equation in part A.
</span>y = x + 6
2 = -4 + 6 = -2 so it satisfies the solution